Solving Linear Inequalities Identifying Solutions To Y < 0.5x + 2

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Introduction

In the realm of mathematics, linear inequalities play a pivotal role in defining regions within a coordinate plane. These inequalities, similar to linear equations, involve variables, coefficients, and constants, but instead of an equality sign (=), they employ inequality symbols such as < (less than), > (greater than), ≤ (less than or equal to), or ≥ (greater than or equal to). Understanding how to identify solutions to linear inequalities is fundamental in various mathematical contexts, including graphing, optimization problems, and systems of inequalities.

This article delves into the process of determining which points are solutions to the linear inequality y < 0.5x + 2. We will explore the underlying concepts, demonstrate the method for verifying solutions, and apply this knowledge to a specific set of points. By the end of this discussion, you will have a solid grasp of how to identify solutions to linear inequalities and confidently apply this skill in your mathematical endeavors.

Understanding Linear Inequalities

Before diving into the specifics of the inequality y < 0.5x + 2, let's first establish a firm understanding of linear inequalities in general. A linear inequality is a mathematical statement that compares two expressions using one of the inequality symbols mentioned earlier. These expressions typically involve variables raised to the power of 1, making them linear. When graphed on a coordinate plane, linear inequalities represent regions rather than specific lines, as is the case with linear equations. The solution set of a linear inequality comprises all the points within the shaded region that satisfy the inequality.

To illustrate this concept, consider the inequality y < 0.5x + 2. This inequality states that the y-coordinate of a point must be less than the value obtained by multiplying the x-coordinate by 0.5 and adding 2. Graphically, this represents the region below the line y = 0.5x + 2. The line itself is not included in the solution set because the inequality is strict (i.e., it uses the < symbol). If the inequality were y ≤ 0.5x + 2, the line would be included, and the region would be shaded up to and including the line.

Verifying Solutions to y < 0.5x + 2

To determine whether a given point is a solution to the linear inequality y < 0.5x + 2, we simply substitute the x and y coordinates of the point into the inequality and check if the resulting statement is true. If the inequality holds true, the point is a solution; otherwise, it is not. This process is straightforward and provides a definitive way to identify solutions without relying solely on graphical representations.

Let's consider the point (-3, -2) as an example. To verify if this point is a solution, we substitute x = -3 and y = -2 into the inequality:

-2 < 0.5(-3) + 2

Simplifying the right side of the inequality, we get:

-2 < -1.5 + 2

-2 < 0.5

Since -2 is indeed less than 0.5, the inequality holds true, and the point (-3, -2) is a solution to y < 0.5x + 2.

Now, let's examine the point (-2, 1). Substituting x = -2 and y = 1 into the inequality, we have:

1 < 0.5(-2) + 2

Simplifying the right side:

1 < -1 + 2

1 < 1

In this case, the inequality is false because 1 is not less than 1. Therefore, the point (-2, 1) is not a solution to y < 0.5x + 2.

By repeating this process for various points, we can systematically identify the solutions to the linear inequality. This method provides a robust and accurate way to determine which points satisfy the given condition.

Analyzing the Given Points

Now, let's apply the method described above to the specific set of points provided: (-3, -2), (-2, 1), (-1, -2), (-1, 2), and (1, -2). We will substitute the coordinates of each point into the inequality y < 0.5x + 2 and determine whether the resulting statement is true or false.

Point (-3, -2)

As we demonstrated earlier, substituting x = -3 and y = -2 into the inequality yields:

-2 < 0.5(-3) + 2

-2 < -1.5 + 2

-2 < 0.5

This inequality is true, so (-3, -2) is a solution.

Point (-2, 1)

Substituting x = -2 and y = 1 into the inequality gives:

1 < 0.5(-2) + 2

1 < -1 + 2

1 < 1

This inequality is false, so (-2, 1) is not a solution.

Point (-1, -2)

Substituting x = -1 and y = -2 into the inequality yields:

-2 < 0.5(-1) + 2

-2 < -0.5 + 2

-2 < 1.5

This inequality is true, so (-1, -2) is a solution.

Point (-1, 2)

Substituting x = -1 and y = 2 into the inequality gives:

2 < 0.5(-1) + 2

2 < -0.5 + 2

2 < 1.5

This inequality is false, so (-1, 2) is not a solution.

Point (1, -2)

Substituting x = 1 and y = -2 into the inequality yields:

-2 < 0.5(1) + 2

-2 < 0.5 + 2

-2 < 2.5

This inequality is true, so (1, -2) is a solution.

Identifying the Solutions

Based on our analysis, the points that satisfy the inequality y < 0.5x + 2 are (-3, -2), (-1, -2), and (1, -2). These points lie in the region below the line y = 0.5x + 2 on the coordinate plane.

The points (-2, 1) and (-1, 2), on the other hand, do not satisfy the inequality. They either lie on the line y = 0.5x + 2 or above it, and therefore are not part of the solution set.

Conclusion

In this article, we have explored the process of identifying solutions to the linear inequality y < 0.5x + 2. We established a clear understanding of linear inequalities, demonstrated the method for verifying solutions by substituting coordinates, and applied this knowledge to a specific set of points. Our analysis revealed that the points (-3, -2), (-1, -2), and (1, -2) are solutions to the inequality, while the points (-2, 1) and (-1, 2) are not.

This skill of identifying solutions to linear inequalities is crucial in various mathematical applications. Whether you are graphing inequalities, solving optimization problems, or working with systems of inequalities, the ability to determine which points satisfy a given inequality is essential for success. By mastering this concept, you will enhance your mathematical toolkit and be well-equipped to tackle a wide range of problems.

Remember, the key to verifying solutions lies in the simple yet powerful technique of substitution. By plugging in the coordinates of a point into the inequality and checking if the resulting statement is true, you can confidently determine whether the point is a solution. Practice this method with various linear inequalities and points to solidify your understanding and build your problem-solving skills. With consistent effort, you will become proficient in identifying solutions to linear inequalities and excel in your mathematical pursuits.