Solving Linear Equations: A Step-by-Step Guide

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Hey there, math enthusiasts! Today, we're diving into the world of linear equations. Specifically, we're going to solve a system of linear equations without even touching a graph! Graphs are cool, but sometimes, a good old algebraic approach is the way to go. Let's tackle this problem together and break it down step by step. We'll be looking at the following system of equations:

{3y+7=5x7x−3y=1\{3y + 7 = 5x \\ 7x - 3y = 1

Before we jump in, let's make sure we're all on the same page. A system of linear equations is simply a set of two or more linear equations that we're trying to solve simultaneously. The goal is to find the values of the variables (in this case, x and y) that satisfy all the equations in the system. There are several methods to solve these systems, and we are going to explore a reliable method to find the values of the unknowns. Remember, in a system of linear equations, each equation represents a straight line. The solution to the system is the point (or points) where these lines intersect. If the lines are parallel, there's no solution. If they're the same line, there are infinitely many solutions. But, let's keep it simple for now, yeah?

So, what's our game plan? Well, there are a couple of popular methods: substitution and elimination. I like elimination. It's often the quickest route. In elimination, we manipulate the equations to eliminate one of the variables. Then we solve for the remaining variable. Finally, we substitute that value back into one of the original equations to find the value of the other variable. Let's get started. Let's rearrange these equations. The key is to get the x and y terms lined up. This makes the elimination process much smoother. Let's rewrite our system of equations like this:

5x−3y=75x - 3y = 7

7x−3y=17x - 3y = 1

Elimination Method

Alright, let's get down to business with the elimination method! To make our lives easier, we want to eliminate either x or y. Take a look at our system of equations:

5x−3y=75x - 3y = 7

7x−3y=17x - 3y = 1

Notice something cool? Both equations have a -3y term. That's perfect for elimination! If we subtract one equation from the other, the y terms will cancel out. Let's subtract the second equation from the first:

(5x−3y)−(7x−3y)=7−1(5x - 3y) - (7x - 3y) = 7 - 1

Now, simplify:

5x−7x−3y−(−3y)=65x - 7x - 3y - (-3y) = 6

−2x=6-2x = 6

See how the y terms vanished? Magic! Now, we just solve for x: Divide both sides by -2:

x=−3x = -3

Boom! We've found the value of x. One down, one to go! Now the question is how do we calculate the value of y? Let's take that step.

Now, we need to find the value of y. We can substitute the value of x we just found (-3) into either of the original equations. I'll pick the first one, but either will work. Remember, the solution to this system must satisfy both equations. Let's plug in x = -3 into the first equation (5x - 3y = 7):

5(−3)−3y=75(-3) - 3y = 7

−15−3y=7-15 - 3y = 7

Add 15 to both sides:

−3y=22-3y = 22

Divide both sides by -3:

y=−223y = -\frac{22}{3}

There we go! We've found both x and y. Our solution is x = -3 and y = -22/3. Awesome! But we should verify. Always check your work! It's a good habit to prevent errors.

Verification of the Solution

Now, let's double-check our work. We'll plug our solution (x = -3, y = -22/3) into both of the original equations to make sure everything holds true. This is a crucial step to ensure the solution is correct.

Equation 1: 3y + 7 = 5x

Substitute x = -3 and y = -22/3:

3∗(−22/3)+7=5∗(−3)3 * (-22/3) + 7 = 5 * (-3)

−22+7=−15-22 + 7 = -15

−15=−15-15 = -15

It checks out! Equation 1 is satisfied.

Equation 2: 7x - 3y = 1

Substitute x = -3 and y = -22/3:

7∗(−3)−3∗(−22/3)=17 * (-3) - 3 * (-22/3) = 1

−21+22=1-21 + 22 = 1

1=11 = 1

And equation 2 is also satisfied! We've confirmed that our solution x = -3 and y = -22/3 is correct. High five! You have successfully solved the system of linear equations. Now, you can apply this method to other systems of linear equations. Practice makes perfect, so don't be afraid to try more problems. You've got this!

This method is efficient and straightforward, making it a great tool for solving linear equations. Remember that the key is to eliminate one variable by manipulating the equations and then solve for the other. Always check your answers to ensure accuracy. If you follow these steps, you will become a linear equation pro in no time.

Additional Tips and Tricks

Now that you've got the basics down, let's level up your linear equation solving skills with some additional tips and tricks. These strategies will help you tackle more complex problems and become even more proficient. Sometimes, you might encounter systems of equations where a direct elimination isn't immediately obvious. In these cases, you might need to multiply one or both equations by a constant before you can eliminate a variable. The goal is to make the coefficients of either x or y opposites so they cancel out when you add the equations. For instance, if you have equations like:

2x+3y=72x + 3y = 7

x−y=1x - y = 1

You could multiply the second equation by 3 to eliminate y. This gives you:

2x+3y=72x + 3y = 7

3x−3y=33x - 3y = 3

Adding these equations, you get 5x = 10, and you can solve for x. Remember, whatever you do to one side of the equation, you must do to the other to maintain the balance. Another useful trick is to recognize special cases. If, after manipulating your equations, you end up with a statement like 0 = 0, this means the system has infinitely many solutions. The two equations represent the same line. If you get a statement like 0 = 5, this means the system has no solution. The lines are parallel and never intersect. This means that no values of x and y can satisfy both equations. Furthermore, always double-check your work. When you're solving for x and y, substitute those values back into the original equations to ensure they satisfy both. This helps to catch any errors and ensures your solution is correct. Practice with a variety of problems. The more problems you solve, the more comfortable you'll become with different types of equations and the elimination method. Try problems with fractions, decimals, and negative numbers to broaden your skills.

Remember, solving linear equations is a fundamental skill in mathematics, so mastering it is extremely important. Don't be afraid to experiment, try different approaches, and learn from your mistakes. With consistent practice and these tips and tricks, you'll become a confident equation solver in no time. You will get better over time. Keep going, and you'll be solving complex systems of equations with ease. It is a fantastic skill to know!