Simplifying The Algebraic Expression $5x^31^3 \cdot (7x^2)^{\frac{1}{3}}$

by ADMIN 74 views

Introduction

In this article, we will delve into the process of simplifying the algebraic expression 5x313â‹…(7x2)135x^31^3 \cdot (7x^2)^{\frac{1}{3}}. This involves understanding the rules of exponents, combining like terms, and expressing the result in a simplified form. Algebraic expressions are fundamental in mathematics, appearing in various branches such as calculus, linear algebra, and differential equations. Mastering the simplification of these expressions is crucial for students and professionals alike. This article will methodically break down each step, ensuring a clear and comprehensive understanding of the process.

Understanding the Expression

To begin, let's dissect the given expression: 5x313â‹…(7x2)135x^31^3 \cdot (7x^2)^{\frac{1}{3}}. This expression consists of several components, each requiring careful consideration. The first part, 5x3135x^31^3, involves a constant (5), a variable (xx) raised to the power of 3, and another constant (1) also raised to the power of 3. The second part, (7x2)13(7x^2)^{\frac{1}{3}}, introduces a fractional exponent, which signifies a radical expression. The entire expression represents the product of these two parts. Simplifying this expression requires applying the rules of exponents, multiplication, and the understanding of fractional powers. We will start by addressing each component separately before combining them to achieve the simplest form. The presence of the fractional exponent particularly highlights the need for careful application of exponent rules to ensure accurate simplification. This process not only simplifies the expression but also enhances our understanding of algebraic manipulation.

Step-by-Step Simplification

Part 1: Simplifying 5x3135x^31^3

The initial step in simplifying the expression involves addressing the first part: 5x3135x^31^3. Here, we observe that 131^3 is simply 1, as any number 1 raised to any power remains 1. Therefore, we can replace 131^3 with 1. The expression then becomes 5x3â‹…15x^3 \cdot 1. Multiplying any term by 1 does not change its value, so 5x3â‹…15x^3 \cdot 1 simplifies to 5x35x^3. This simplification is straightforward but crucial, as it reduces the complexity of the initial term and allows us to focus on the remaining parts of the expression. This elementary step underscores the importance of recognizing and applying basic arithmetic principles in algebraic simplification. By reducing this component, we set the stage for addressing the more complex fractional exponent in the second part of the expression. This methodical approach is key to tackling complex algebraic problems effectively.

Part 2: Simplifying (7x2)13(7x^2)^{\frac{1}{3}}

Next, we tackle the second part of the expression: (7x2)13(7x^2)^{\frac{1}{3}}. This term involves a fractional exponent, which indicates a radical. Specifically, an exponent of 13\frac{1}{3} represents the cube root. Therefore, (7x2)13(7x^2)^{\frac{1}{3}} can be rewritten as 7x23\sqrt[3]{7x^2}. This notation change helps us visualize the operation we need to perform. To further simplify, we consider whether we can extract any perfect cubes from the expression inside the cube root. In this case, neither 7 nor x2x^2 contains a perfect cube factor. The prime factorization of 7 is simply 7, and the exponent of xx is 2, which is less than 3. Thus, we cannot simplify the radical any further. The term 7x23\sqrt[3]{7x^2} remains in this form as the simplest representation. Understanding fractional exponents and their relation to radicals is crucial for simplifying such expressions. This step highlights the importance of recognizing when a radical cannot be simplified further, which is a common scenario in algebraic manipulations.

Part 3: Combining the Simplified Parts

Now that we have simplified both parts of the expression, we can combine them. We found that 5x3135x^31^3 simplifies to 5x35x^3, and (7x2)13(7x^2)^{\frac{1}{3}} simplifies to 7x23\sqrt[3]{7x^2}. The original expression was a product of these two parts, so we now multiply the simplified forms: 5x3â‹…7x235x^3 \cdot \sqrt[3]{7x^2}. This expression is the product of a monomial and a radical term. To express this in a more compact form, we can leave it as is or rewrite the radical using the fractional exponent notation. In this case, we have 5x3â‹…(7x2)135x^3 \cdot (7x^2)^{\frac{1}{3}}. There are no like terms to combine, and no further simplification can be done using basic algebraic techniques. This combined form represents the simplified version of the original expression. This step demonstrates how simplifying individual components before combining them can lead to a manageable final expression. The final form may not always be a single term but can often involve a combination of terms, as seen here.

Final Simplified Expression

After simplifying each part of the original expression and combining them, we arrive at the final simplified form: 5x3â‹…(7x2)135x^3 \cdot (7x^2)^{\frac{1}{3}}. This expression represents the most reduced form achievable through standard algebraic simplification techniques. The process involved simplifying 5x3135x^31^3 to 5x35x^3, simplifying (7x2)13(7x^2)^{\frac{1}{3}} to 7x23\sqrt[3]{7x^2} (or equivalently (7x2)13(7x^2)^{\frac{1}{3}}), and then combining these simplified parts. The final expression retains the product of the monomial and the radical term, as there are no further simplifications possible. This result underscores the importance of a systematic approach to simplifying algebraic expressions, breaking down complex problems into smaller, manageable steps. The ability to correctly manipulate exponents and radicals is crucial in achieving the simplest form. This final expression is not only mathematically sound but also provides a clear and concise representation of the original expression in its most reduced form.

Conclusion

In conclusion, we successfully simplified the algebraic expression 5x313â‹…(7x2)135x^31^3 \cdot (7x^2)^{\frac{1}{3}} to its final form: 5x3â‹…(7x2)135x^3 \cdot (7x^2)^{\frac{1}{3}}. This process involved several key steps, including the simplification of 5x3135x^31^3 to 5x35x^3, the conversion of (7x2)13(7x^2)^{\frac{1}{3}} to its radical form 7x23\sqrt[3]{7x^2} (and recognizing it could not be simplified further), and the subsequent combination of these simplified terms. Understanding the properties of exponents, particularly fractional exponents, and the rules for simplifying radicals were critical to this process. The step-by-step approach ensured accuracy and clarity, demonstrating how complex algebraic expressions can be simplified through methodical application of mathematical principles. This exercise not only provides a solution to the specific problem but also reinforces the fundamental skills necessary for algebraic manipulation. The simplified expression, 5x3â‹…(7x2)135x^3 \cdot (7x^2)^{\frac{1}{3}}, represents the most concise form of the original expression, highlighting the power of algebraic simplification techniques.