Simplifying Expressions With Exponents A Step-by-Step Guide To (16x^4/y^8)^(-1/4)

by ADMIN 82 views

Introduction

In this article, we will delve into the simplification of the expression (16x4y8)βˆ’14{\left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}}}. This problem involves understanding the rules of exponents, particularly negative and fractional exponents, and applying them correctly to simplify the given expression. Mastery of these concepts is crucial for anyone studying algebra and calculus, as they frequently appear in various mathematical contexts. We will break down the problem step by step, ensuring a clear and comprehensive understanding of each operation performed. This exploration will not only enhance your algebraic skills but also build a solid foundation for more advanced mathematical topics. Let’s begin by dissecting the components of the expression and identifying the order in which we should apply the exponent rules.

Breaking Down the Expression

To effectively simplify {\left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}}\, we must first understand the role of each component. The expression consists of a fraction, \(\frac{16 x^4}{y^8}}, raised to a negative fractional exponent, βˆ’14{-\frac{1}{4}}. A negative exponent indicates that we need to take the reciprocal of the base. In other words, aβˆ’n=1an{a^{-n} = \frac{1}{a^n}}. A fractional exponent, on the other hand, represents a root. Specifically, a1n{a^{\frac{1}{n}}} is the n{n}-th root of a{a}. For instance, a12{a^{\frac{1}{2}}} is the square root of a{a}, and a13{a^{\frac{1}{3}}} is the cube root of a{a}. In our case, the exponent βˆ’14{-\frac{1}{4}} combines both these concepts, meaning we need to take the reciprocal of the base and then find its fourth root. This might seem complex, but by addressing each part systematically, we can simplify the expression efficiently. We will start by applying the negative exponent and then proceed with the fractional exponent. Understanding these fundamental exponent rules is key to tackling this and similar problems successfully.

Applying the Negative Exponent

The first step in simplifying (16x4y8)βˆ’14{\left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}}} is to address the negative exponent, βˆ’14{-\frac{1}{4}}. As discussed earlier, a negative exponent implies taking the reciprocal of the base. This means we need to invert the fraction inside the parentheses. Applying this rule, we get:

(16x4y8)βˆ’14=(y816x4)14{ \left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}} = \left(\frac{y^8}{16 x^4}\right)^{\frac{1}{4}} }

By taking the reciprocal, we have transformed the expression into a more manageable form where the exponent is now a positive fraction. This positive fractional exponent represents taking the fourth root, which we will address in the next step. It's important to understand that flipping the fraction is a direct consequence of the negative exponent rule, and it simplifies the problem by allowing us to work with positive exponents and roots. This step is crucial because it sets the stage for further simplification using the properties of radicals. Now, let's move on to dealing with the fractional exponent and see how it affects the terms inside the parentheses. Understanding this transformation is vital for mastering exponent manipulations in algebra.

Simplifying the Fractional Exponent

Now that we have {\left(\frac{y^8}{16 x^4}\right)^{\frac{1}{4}}\, the next step is to apply the **fractional exponent** \(\frac{1}{4}}. This exponent signifies taking the fourth root of the entire fraction. Recall that a1n{a^{\frac{1}{n}}} means the n{n}-th root of a{a}. Therefore, we need to find the fourth root of both the numerator and the denominator. This can be expressed as:

(y816x4)14=(y8)14(16x4)14{ \left(\frac{y^8}{16 x^4}\right)^{\frac{1}{4}} = \frac{(y^8)^{\frac{1}{4}}}{(16 x^4)^{\frac{1}{4}}} }

Applying the power of a power rule, which states that (am)n=amn{(a^m)^n = a^{mn}}, we can further simplify the numerator and the denominator. For the numerator, we have (y8)14=y8β‹…14=y2{(y^8)^{\frac{1}{4}} = y^{8 \cdot \frac{1}{4}} = y^2}. For the denominator, we need to consider both the constant and the variable terms. We have {(16 x^4)^{\frac{1}{4}} = 16^{\frac{1}{4}} \cdot (x^4)^{\frac{1}{4}}\, where \(16^{\frac{1}{4}}} is the fourth root of 16, which is 2, and (x4)14=x4β‹…14=x{(x^4)^{\frac{1}{4}} = x^{4 \cdot \frac{1}{4}} = x}. Thus, the denominator simplifies to 2x{2x}. This meticulous breakdown of applying the fractional exponent helps in understanding how each part of the expression is affected, leading us closer to the final simplified form. Next, we will combine these simplified terms to get the final result.

Combining and Final Simplification

After applying the fractional exponent, we have simplified the numerator and the denominator separately. The numerator (y8)14{(y^8)^{\frac{1}{4}}} simplified to y2{y^2}, and the denominator (16x4)14{(16 x^4)^{\frac{1}{4}}} simplified to 2x{2x}. Now, we combine these results to get the simplified fraction:

(y8)14(16x4)14=y22x{ \frac{(y^8)^{\frac{1}{4}}}{(16 x^4)^{\frac{1}{4}}} = \frac{y^2}{2x} }

This is the simplified form of the original expression (16x4y8)βˆ’14{\left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}}}. We have successfully applied the negative exponent by taking the reciprocal and then applied the fractional exponent by finding the fourth root of both the numerator and the denominator. The final step is to present the result in its simplest form. In this case, y22x{\frac{y^2}{2x}} is already in its simplest form, as there are no common factors to further reduce the fraction. Understanding how to combine these simplified components is crucial for completing the problem and ensuring the final result is accurate and in its most concise form. This process showcases the importance of breaking down complex problems into smaller, manageable steps, each building upon the previous one to reach the solution.

Conclusion

In summary, we have successfully simplified the expression (16x4y8)βˆ’14{\left(\frac{16 x^4}{y^8}\right)^{-\frac{1}{4}}} to y22x{\frac{y^2}{2x}}. This process involved several key steps, each demonstrating the application of fundamental exponent rules. First, we addressed the negative exponent by taking the reciprocal of the fraction, transforming the expression into (y816x4)14{\left(\frac{y^8}{16 x^4}\right)^{\frac{1}{4}}}. Then, we tackled the fractional exponent by finding the fourth root of both the numerator and the denominator. This involved recognizing that 1614=2{16^{\frac{1}{4}} = 2} and applying the power of a power rule to simplify the variables. By breaking down the problem into these steps, we were able to methodically simplify the expression and arrive at the final answer. This exercise underscores the importance of understanding and applying exponent rules effectively, as they are essential tools in algebra and beyond. Mastering these concepts not only helps in simplifying expressions but also builds a strong foundation for tackling more complex mathematical problems. The ability to dissect and solve such problems is a testament to a solid grasp of algebraic principles.