Simplifying Algebraic Expressions With Exponents

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In mathematics, simplifying algebraic expressions is a fundamental skill. It allows us to work with complex equations and formulas more easily. One area where simplification is crucial is when dealing with exponents. Exponents provide a concise way to express repeated multiplication, and understanding how to manipulate them is essential for various mathematical operations. In this article, we'll delve into the simplification of algebraic expressions involving exponents, focusing on three distinct examples. We'll cover the basic rules of exponents, demonstrate how to apply these rules step-by-step, and provide explanations to ensure a clear understanding of the simplification process. Whether you're a student learning algebra or someone looking to refresh your math skills, this guide will equip you with the knowledge and techniques to confidently simplify expressions with exponents.

1. Simplifying x6y3x2y6{\frac{x^6 y^3}{x^2 y^6}}

The first expression we'll tackle is x6y3x2y6{\frac{x^6 y^3}{x^2 y^6}}. This expression involves variables raised to different powers, and our goal is to simplify it by applying the rules of exponents. The key rule we'll use here is the quotient rule, which states that when dividing expressions with the same base, we subtract the exponents. Let's break down the simplification process step-by-step:

Step 1: Apply the Quotient Rule

The quotient rule of exponents states that for any non-zero base a and exponents m and n, aman=amβˆ’n{\frac{a^m}{a^n} = a^{m-n}}. We can apply this rule to both the x and y terms in our expression:

  • For the x terms: x6x2=x6βˆ’2=x4{\frac{x^6}{x^2} = x^{6-2} = x^4}
  • For the y terms: y3y6=y3βˆ’6=yβˆ’3{\frac{y^3}{y^6} = y^{3-6} = y^{-3}}

So, after applying the quotient rule, our expression becomes x4yβˆ’3{x^4 y^{-3}}.

Step 2: Eliminate Negative Exponents

Negative exponents indicate reciprocals. Specifically, aβˆ’n=1an{a^{-n} = \frac{1}{a^n}}. We have a negative exponent in our expression, the yβˆ’3{y^{-3}} term. To eliminate it, we take the reciprocal of yβˆ’3{y^{-3}}, which is 1y3{\frac{1}{y^3}}.

Therefore, we can rewrite x4yβˆ’3{x^4 y^{-3}} as x4β‹…1y3{x^4 \cdot \frac{1}{y^3}}.

Step 3: Simplify the Expression

Finally, we combine the terms to get our simplified expression. Multiplying x4{x^4} by 1y3{\frac{1}{y^3}} gives us x4y3{\frac{x^4}{y^3}}. This is the simplified form of the original expression.

In summary, simplifying x6y3x2y6{\frac{x^6 y^3}{x^2 y^6}} involves applying the quotient rule to subtract exponents and then eliminating negative exponents by taking reciprocals. The simplified expression is x4y3{\frac{x^4}{y^3}}. This process demonstrates the power of exponent rules in making algebraic expressions more manageable and easier to understand. By breaking down the problem into smaller steps, we can clearly see how each rule contributes to the final result.

2. Simplifying 12m7n54mβˆ’3n2{\frac{12m^7 n^5}{4m^{-3} n^2}}

Now, let's move on to the second expression: 12m7n54mβˆ’3n2{\frac{12m^7 n^5}{4m^{-3} n^2}}. This expression includes coefficients (the numerical parts) along with variables raised to powers. To simplify this, we'll again use the quotient rule of exponents, but we'll also need to consider how to simplify the coefficients. Here’s a step-by-step breakdown:

Step 1: Simplify the Coefficients

First, we simplify the coefficients by dividing 12 by 4. This gives us 124=3{\frac{12}{4} = 3}. So, our expression now looks like 3β‹…m7n5mβˆ’3n2{3 \cdot \frac{m^7 n^5}{m^{-3} n^2}}.

Step 2: Apply the Quotient Rule to Variables

Next, we apply the quotient rule to the variables with exponents. Remember, the quotient rule states that aman=amβˆ’n{\frac{a^m}{a^n} = a^{m-n}}. We apply this rule separately to the m and n terms:

  • For the m terms: m7mβˆ’3=m7βˆ’(βˆ’3)=m7+3=m10{\frac{m^7}{m^{-3}} = m^{7-(-3)} = m^{7+3} = m^{10}}
  • For the n terms: n5n2=n5βˆ’2=n3{\frac{n^5}{n^2} = n^{5-2} = n^3}

After applying the quotient rule, our expression becomes 3m10n3{3m^{10}n^3}.

Step 3: Combine the Terms

Finally, we combine the simplified coefficient and variable terms to get our final simplified expression. Multiplying the coefficient 3 with the variable terms m10{m^{10}} and n3{n^3} gives us 3m10n3{3m^{10}n^3}. This is the fully simplified form of the original expression.

In this example, we successfully simplified 12m7n54mβˆ’3n2{\frac{12m^7 n^5}{4m^{-3} n^2}} by first simplifying the coefficients and then applying the quotient rule to the variables. The resulting simplified expression is 3m10n3{3m^{10}n^3}. This problem highlights the importance of addressing each component of the expressionβ€”coefficients and variablesβ€”systematically to arrive at the simplest form. The use of the quotient rule, especially when dealing with negative exponents, is crucial in this process. By understanding and applying these rules, complex algebraic expressions can be simplified into manageable and understandable forms.

3. Simplifying 16a5βˆ’6b4βˆ’3c6βˆ’44{\frac{16a^{5-6} b^{4-3} c^{6-4}}{4}}

Our third and final expression is 16a5βˆ’6b4βˆ’3c6βˆ’44{\frac{16a^{5-6} b^{4-3} c^{6-4}}{4}}. This expression presents a slight variation from the previous ones, as the exponents involve subtractions that need to be evaluated first. Additionally, we have coefficients and multiple variables, requiring us to apply the exponent rules and simplify the coefficients systematically. Let's break down the simplification process step-by-step:

Step 1: Simplify the Exponents

Before applying any exponent rules, we need to simplify the exponents by performing the subtractions:

  • For the a term: 5βˆ’6=βˆ’1{5 - 6 = -1}, so we have aβˆ’1{a^{-1}}
  • For the b term: 4βˆ’3=1{4 - 3 = 1}, so we have b1{b^1} (which is simply b)
  • For the c term: 6βˆ’4=2{6 - 4 = 2}, so we have c2{c^2}

Now our expression looks like 16aβˆ’1bc24{\frac{16a^{-1} b c^2}{4}}.

Step 2: Simplify the Coefficients

Next, we simplify the coefficients by dividing 16 by 4. This gives us 164=4{\frac{16}{4} = 4}. So, our expression becomes 4aβˆ’1bc2{4a^{-1}bc^2}.

Step 3: Eliminate Negative Exponents

We have a negative exponent in the aβˆ’1{a^{-1}} term. To eliminate it, we take the reciprocal of aβˆ’1{a^{-1}}, which is 1a{\frac{1}{a}}. This means we rewrite aβˆ’1{a^{-1}} as 1a{\frac{1}{a}}.

Thus, our expression becomes 4β‹…1aβ‹…bβ‹…c2{4 \cdot \frac{1}{a} \cdot b \cdot c^2}.

Step 4: Combine the Terms

Finally, we combine all the terms to get our simplified expression. Multiplying the terms together, we get 4bc2a{\frac{4bc^2}{a}}. This is the simplified form of the original expression.

In simplifying 16a5βˆ’6b4βˆ’3c6βˆ’44{\frac{16a^{5-6} b^{4-3} c^{6-4}}{4}}, we first simplified the exponents by performing the subtractions, then simplified the coefficients, and finally eliminated the negative exponent by taking the reciprocal. The resulting simplified expression is 4bc2a{\frac{4bc^2}{a}}. This example underscores the importance of following the order of operations and addressing each part of the expression methodically. By simplifying the exponents first, then the coefficients, and finally dealing with any negative exponents, we can arrive at the most simplified form of the algebraic expression.

In conclusion, simplifying algebraic expressions with exponents involves a systematic application of exponent rules and algebraic principles. Through the examples provided, we've demonstrated how to apply the quotient rule, simplify coefficients, and handle negative exponents. Each step in the simplification process is crucial to arriving at the most concise and understandable form of the expression. Mastering these techniques is essential for success in algebra and higher-level mathematics, as it enables us to manipulate and solve equations more efficiently. By practicing these methods and understanding the underlying rules, anyone can become proficient in simplifying algebraic expressions with exponents.

  1. How to Simplify the Expression x6y3x2y6{\frac{x^6 y^3}{x^2 y^6}}?
  2. How to Simplify the Expression 12m7n54mβˆ’3n2{\frac{12m^7 n^5}{4m^{-3} n^2}}?
  3. How to Simplify the Expression 16a5βˆ’6b4βˆ’3c6βˆ’44{\frac{16a^{5-6} b^{4-3} c^{6-4}}{4}}?