Polynomial Equivalence A Step By Step Guide

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#h1 Understanding Polynomial Equivalence: A Comprehensive Guide

In the realm of mathematics, polynomials hold a crucial position, serving as the bedrock for various algebraic manipulations and problem-solving techniques. Understanding polynomial equivalence is paramount for students, educators, and professionals alike. This article delves into the intricacies of determining equivalent expressions, focusing on the practical application of algebraic identities and simplification methods. We will explore the process of expanding and factoring polynomials, providing clarity on how different expressions can represent the same mathematical relationship. The journey through polynomial equivalence requires a keen eye for detail and a solid grasp of fundamental algebraic principles. To begin, let's consider the importance of recognizing equivalent expressions. In many mathematical contexts, an expression can be represented in multiple forms, each with its unique advantages depending on the situation. For instance, a factored form might be more useful for finding roots, while an expanded form might be more convenient for evaluating the polynomial at a specific point. Therefore, the ability to navigate between different forms of the same polynomial is an invaluable skill. Furthermore, understanding polynomial equivalence is not just about manipulating symbols; it's about understanding the underlying mathematical relationships. When we say two expressions are equivalent, we mean they produce the same output for any given input. This concept is fundamental to the logical structure of mathematics and is crucial for making valid inferences and deductions. As we delve deeper into this topic, we will encounter various techniques for proving equivalence, including algebraic manipulation, substitution, and graphical methods. Each of these methods provides a unique perspective on the concept of equivalence and reinforces the idea that mathematical expressions are not static entities but dynamic representations of underlying relationships. The journey through polynomial equivalence is a journey through the heart of algebra, where the abstract symbols come to life and reveal the beautiful structure of mathematical thought. Whether you're a student grappling with algebraic concepts or a seasoned professional seeking to refresh your skills, this exploration will provide you with the tools and insights necessary to master the art of polynomial equivalence.

Exploring Polynomial Expressions and Equivalence

When dealing with polynomial expressions, it's essential to understand that different forms can represent the same mathematical relationship. Polynomial equivalence is the concept that two polynomials are equivalent if they produce the same output for every input value. This equivalence can be demonstrated through various algebraic manipulations and identities. To truly grasp polynomial equivalence, it’s crucial to delve into the nature of polynomials themselves. A polynomial is an expression consisting of variables and coefficients, combined using addition, subtraction, and non-negative integer exponents. The degree of a polynomial is the highest power of the variable in the expression. Understanding these fundamental properties allows us to classify and manipulate polynomials effectively. One of the key techniques for demonstrating polynomial equivalence is expansion. Expansion involves multiplying out terms and simplifying the expression to a standard form. This often involves using the distributive property, which states that a(b + c) = ab + ac. By applying this property repeatedly, we can transform a factored form into an expanded form. Another important technique is factoring, which is the reverse process of expansion. Factoring involves breaking down a polynomial into a product of simpler expressions. This often requires recognizing patterns, such as the difference of squares (a^2 - b^2 = (a + b)(a - b)) or perfect square trinomials (a^2 + 2ab + b^2 = (a + b)^2). Mastering these factoring techniques is crucial for simplifying expressions and solving equations. In addition to expansion and factoring, substitution is a powerful tool for demonstrating polynomial equivalence. Substitution involves replacing variables with specific values to check if two expressions produce the same output. If two polynomials are equivalent, they should yield the same result for any valid substitution. This method can be particularly useful for verifying equivalences or identifying potential errors in algebraic manipulations. Graphical methods can also provide insights into polynomial equivalence. The graph of a polynomial visually represents its behavior over a range of input values. If two polynomials are equivalent, their graphs will be identical. This graphical perspective can be particularly helpful for understanding the relationship between the algebraic form of a polynomial and its visual representation. By exploring these various techniques, we gain a deeper appreciation for the concept of polynomial equivalence. It's not just about manipulating symbols; it's about understanding the underlying mathematical relationships and the different ways they can be represented.

Deconstructing the Expression (x+8)2(x+8)^2

Let's take a closer look at the expression (x+8)2(x+8)^2. To determine its equivalent form, we need to expand it using the algebraic identity for the square of a binomial, which is (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. Applying this identity to our expression, we substitute aa with xx and bb with 88. This gives us (x+8)2=x2+2(x)(8)+82(x+8)^2 = x^2 + 2(x)(8) + 8^2. Now, we simplify the expression step-by-step. First, we multiply 2(x)(8)2(x)(8) to get 16x16x. Next, we calculate 828^2, which is 6464. Putting it all together, we have x2+16x+64x^2 + 16x + 64. This expanded form is the equivalent of (x+8)2(x+8)^2. The expansion of (x+8)2(x+8)^2 is a classic example of how algebraic identities simplify complex expressions. The binomial theorem, which generalizes this pattern for higher powers, is a fundamental concept in algebra. Understanding these patterns not only aids in simplification but also provides insights into the structure of polynomials. Now, let's consider why this expansion is important. The expanded form x2+16x+64x^2 + 16x + 64 reveals the quadratic nature of the expression, making it easier to identify its properties, such as the coefficients and the constant term. This form is particularly useful when solving quadratic equations or analyzing the graph of the corresponding parabola. Moreover, the expanded form allows us to compare this expression with other polynomials more easily. For instance, we can quickly determine if it is equivalent to another quadratic expression by comparing the coefficients of the corresponding terms. In contrast, the factored form (x+8)2(x+8)^2 highlights the root of the polynomial, which is x=βˆ’8x = -8. This form is advantageous when we want to find the zeros of the function or understand its behavior near the root. The ability to switch between the factored and expanded forms is a testament to the power of algebraic manipulation. It allows us to view the same expression from different perspectives, each offering unique insights into its properties. In conclusion, the expression (x+8)2(x+8)^2 is equivalent to x2+16x+64x^2 + 16x + 64 when expanded using the binomial identity. This expansion not only simplifies the expression but also reveals its underlying structure and properties. Understanding this process is crucial for mastering polynomial algebra and solving related problems.

Analyzing the Expression (x+81)(xβˆ’81)(x+81)(x-81)

Moving on, let's analyze the expression (x+81)(xβˆ’81)(x+81)(x-81). This expression is in the form of a difference of squares, which has a specific algebraic identity: (a+b)(aβˆ’b)=a2βˆ’b2(a+b)(a-b) = a^2 - b^2. Applying this identity, we substitute aa with xx and bb with 8181. This gives us (x+81)(xβˆ’81)=x2βˆ’812(x+81)(x-81) = x^2 - 81^2. To simplify further, we need to calculate 81281^2. Multiplying 8181 by itself, we get 65616561. Therefore, the equivalent expression is x2βˆ’6561x^2 - 6561. The difference of squares identity is a cornerstone of algebraic simplification. It provides a shortcut for expanding expressions of this form, saving time and reducing the risk of errors. Recognizing this pattern is crucial for efficient algebraic manipulation. Now, let's delve deeper into the significance of this simplification. The expression x2βˆ’6561x^2 - 6561 is a quadratic binomial, lacking the linear term (the term with xx). This absence of the linear term has implications for the graph of the corresponding function, which is a parabola centered on the y-axis. The roots of this polynomial are x=81x = 81 and x=βˆ’81x = -81, which can be easily identified from the factored form (x+81)(xβˆ’81)(x+81)(x-81). These roots are the points where the parabola intersects the x-axis. The difference of squares pattern also has applications in various areas of mathematics, including calculus and complex numbers. For instance, it can be used to factor expressions involving complex conjugates, which are pairs of complex numbers that differ only in the sign of their imaginary part. In contrast to the expanded form x2βˆ’6561x^2 - 6561, the factored form (x+81)(xβˆ’81)(x+81)(x-81) highlights the roots of the polynomial. This form is particularly useful when we want to solve equations or analyze the behavior of the function near its roots. The ability to move between these forms is a key skill in algebra, allowing us to tackle problems from different angles. In summary, the expression (x+81)(xβˆ’81)(x+81)(x-81) is equivalent to x2βˆ’6561x^2 - 6561 when simplified using the difference of squares identity. This simplification not only reveals the structure of the polynomial but also provides insights into its properties and behavior.

Evaluating the Expression (x+8i)2(x+8i)^2

Next, let's evaluate the expression (x+8i)2(x+8i)^2, where ii represents the imaginary unit, defined as i2=βˆ’1i^2 = -1. To find its equivalent form, we again use the algebraic identity for the square of a binomial: (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. Substituting aa with xx and bb with 8i8i, we get (x+8i)2=x2+2(x)(8i)+(8i)2(x+8i)^2 = x^2 + 2(x)(8i) + (8i)^2. Now, we simplify the expression. First, we multiply 2(x)(8i)2(x)(8i) to get 16xi16xi. Next, we calculate (8i)2(8i)^2, which is 64i264i^2. Since i2=βˆ’1i^2 = -1, we have 64i2=βˆ’6464i^2 = -64. Putting it all together, the equivalent expression is x2+16xiβˆ’64x^2 + 16xi - 64. The presence of the imaginary unit ii indicates that this polynomial involves complex numbers. Complex numbers extend the real number system by including a component that is a multiple of ii. This extension is crucial for solving certain types of equations and has applications in various fields, including electrical engineering and quantum mechanics. The expansion of (x+8i)2(x+8i)^2 demonstrates how algebraic identities can be applied to expressions involving complex numbers. The same rules of algebra apply, but we must remember the fundamental property of ii: its square is -1. This property allows us to simplify expressions and obtain a final result that is also a complex number. Now, let's consider the implications of this expansion. The expression x2+16xiβˆ’64x^2 + 16xi - 64 is a complex quadratic polynomial. It has both a real part (x2βˆ’64x^2 - 64) and an imaginary part (16xi16xi). The roots of this polynomial will also be complex numbers, reflecting the fundamental theorem of algebra, which states that a polynomial of degree nn has nn complex roots (counting multiplicities). In contrast to the original form (x+8i)2(x+8i)^2, the expanded form x2+16xiβˆ’64x^2 + 16xi - 64 reveals the real and imaginary components of the polynomial more clearly. This form is particularly useful when we want to analyze the behavior of the polynomial in the complex plane or solve complex equations. The ability to manipulate expressions involving complex numbers is a valuable skill in advanced mathematics. It allows us to explore a richer mathematical landscape and solve problems that are not solvable within the realm of real numbers alone. In conclusion, the expression (x+8i)2(x+8i)^2 is equivalent to x2+16xiβˆ’64x^2 + 16xi - 64 when expanded using the binomial identity and the properties of complex numbers. This simplification highlights the interplay between algebra and complex analysis, providing a deeper understanding of mathematical structures.

Simplifying the Expression (x+16)(x+4)(x+16)(x+4)

Finally, let's simplify the expression (x+16)(x+4)(x+16)(x+4). To find its equivalent form, we need to multiply the two binomials. We can do this using the distributive property (also known as the FOIL method): (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d) = ac + ad + bc + bd. Applying this to our expression, we have (x+16)(x+4)=x(x)+x(4)+16(x)+16(4)(x+16)(x+4) = x(x) + x(4) + 16(x) + 16(4). Now, we simplify each term. x(x)x(x) is x2x^2, x(4)x(4) is 4x4x, 16(x)16(x) is 16x16x, and 16(4)16(4) is 6464. So, we have x2+4x+16x+64x^2 + 4x + 16x + 64. To further simplify, we combine the like terms 4x4x and 16x16x, which gives us 20x20x. Therefore, the equivalent expression is x2+20x+64x^2 + 20x + 64. This process of multiplying binomials is a fundamental skill in algebra. The distributive property provides a systematic way to ensure that each term in the first binomial is multiplied by each term in the second binomial. Mastering this technique is essential for simplifying polynomial expressions and solving equations. Now, let's consider the characteristics of the simplified expression. The polynomial x2+20x+64x^2 + 20x + 64 is a quadratic trinomial. It has a leading coefficient of 1, a linear coefficient of 20, and a constant term of 64. This form is useful for analyzing the properties of the polynomial, such as its roots and its graph. The roots of this polynomial can be found by factoring or using the quadratic formula. Factoring involves finding two numbers that multiply to 64 and add to 20. These numbers are 4 and 16, which confirms our original expression (x+16)(x+4)(x+16)(x+4). The roots of the polynomial are therefore x=βˆ’4x = -4 and x=βˆ’16x = -16. The factored form (x+16)(x+4)(x+16)(x+4) highlights these roots, while the expanded form x2+20x+64x^2 + 20x + 64 reveals the coefficients and the constant term. Both forms offer valuable insights into the behavior of the polynomial. In conclusion, the expression (x+16)(x+4)(x+16)(x+4) is equivalent to x2+20x+64x^2 + 20x + 64 when simplified using the distributive property. This simplification demonstrates the process of multiplying binomials and provides a deeper understanding of polynomial structure and properties.

Determining the Correct Equivalent Expression

After thoroughly analyzing each expression, we can now determine the correct equivalent form for (x+8)2(x+8)^2. We expanded (x+8)2(x+8)^2 using the binomial identity (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2, which gave us x2+16x+64x^2 + 16x + 64. This is the expanded form of the original expression. The other options we examined were: (x+81)(xβˆ’81)(x+81)(x-81), which simplifies to x2βˆ’6561x^2 - 6561 using the difference of squares identity; (x+8i)2(x+8i)^2, which simplifies to x2+16xiβˆ’64x^2 + 16xi - 64 using the binomial identity and the properties of complex numbers; and (x+16)(x+4)(x+16)(x+4), which simplifies to x2+20x+64x^2 + 20x + 64 using the distributive property. None of these expressions match x2+16x+64x^2 + 16x + 64. Therefore, the correct equivalent expression for (x+8)2(x+8)^2 is x2+16x+64x^2 + 16x + 64, which we obtained by applying the binomial identity and simplifying the resulting terms. The process of determining equivalent expressions involves careful application of algebraic rules and identities. It requires a systematic approach to ensure that each step is valid and that no errors are introduced. This process not only yields the correct answer but also reinforces our understanding of algebraic principles. Now, let's reflect on the significance of this determination. Finding the equivalent form of an expression is a fundamental skill in algebra. It allows us to manipulate expressions into different forms, each of which may be more suitable for a particular purpose. For instance, the expanded form of a polynomial is often easier to evaluate, while the factored form is more useful for finding roots. The ability to switch between different forms of an expression is a key to solving a wide range of algebraic problems. In this case, we started with the expression (x+8)2(x+8)^2 and found its equivalent expanded form. This involved recognizing the binomial pattern and applying the appropriate identity. The other options presented different algebraic patterns, such as the difference of squares and complex numbers. By analyzing each option carefully, we were able to eliminate the incorrect choices and identify the correct equivalent expression. In conclusion, the correct equivalent expression for (x+8)2(x+8)^2 is x2+16x+64x^2 + 16x + 64. This determination was made through careful application of algebraic principles and a systematic analysis of the given options. This process underscores the importance of mastering algebraic techniques for solving mathematical problems.

#h2 Conclusion

In conclusion, understanding polynomial equivalence is a cornerstone of algebraic proficiency. Through this exploration, we've dissected various polynomial expressions, applying algebraic identities and simplification techniques to unveil their equivalent forms. The journey began with a fundamental question about the expression (x+8)2(x+8)^2 and led us through a detailed analysis of several algebraic manipulations. We expanded binomials, recognized difference of squares patterns, and even delved into the realm of complex numbers. Each step reinforced the importance of understanding algebraic identities and applying them systematically. The correct equivalent expression for (x+8)2(x+8)^2 was determined to be x2+16x+64x^2 + 16x + 64, a result obtained by meticulously applying the binomial identity. This process highlighted the significance of careful algebraic manipulation and the power of recognizing patterns. Beyond the specific problem, this exploration has broader implications for mathematical understanding. The ability to transform expressions into equivalent forms is a versatile skill that extends to various areas of mathematics. It allows us to solve equations, simplify complex expressions, and gain deeper insights into mathematical relationships. The concepts we've discussed, such as the distributive property, the difference of squares identity, and the properties of complex numbers, are fundamental building blocks of algebra. Mastering these concepts is crucial for success in higher-level mathematics and related fields. Furthermore, the process of analyzing and simplifying expressions fosters critical thinking and problem-solving skills. It encourages us to approach mathematical challenges with a systematic mindset, breaking down complex problems into smaller, manageable steps. This approach is not only valuable in mathematics but also in other areas of life. As we conclude this exploration, it's important to emphasize the ongoing nature of learning in mathematics. There is always more to discover, more patterns to recognize, and more connections to make. The journey through polynomial equivalence is just one step on the path to mathematical mastery. By continuing to explore and practice, we can deepen our understanding and unlock the beauty and power of mathematics.

#h2 FAQs About Polynomial Equivalence

What does it mean for two polynomial expressions to be equivalent?

Two polynomial expressions are equivalent if they produce the same output for every input value. This means that no matter what value you substitute for the variable, both expressions will yield the same result. Equivalence implies that the expressions represent the same mathematical relationship, even if they appear different on the surface. This concept is crucial for simplifying expressions, solving equations, and understanding the underlying structure of polynomials. For example, the expressions (x+1)2(x+1)^2 and x2+2x+1x^2 + 2x + 1 are equivalent because they produce the same output for any value of xx. Understanding equivalence allows us to manipulate expressions into different forms without changing their fundamental meaning. This is particularly useful when we want to solve equations or analyze the behavior of a function. There are various techniques for demonstrating equivalence, including algebraic manipulation, substitution, and graphical methods. Algebraic manipulation involves applying the rules of algebra to transform one expression into another. This often involves expanding, factoring, and combining like terms. Substitution involves replacing the variable with specific values to check if the expressions produce the same output. If two polynomials are equivalent, they should yield the same result for any valid substitution. Graphical methods involve plotting the graphs of the expressions and comparing them. If the graphs are identical, the expressions are equivalent. The concept of polynomial equivalence is not limited to simple expressions. It extends to more complex polynomials and systems of equations. In these cases, the techniques for demonstrating equivalence may be more involved, but the underlying principle remains the same: two expressions are equivalent if they represent the same mathematical relationship. Understanding polynomial equivalence is a cornerstone of algebraic proficiency. It enables us to manipulate expressions with confidence, solve equations effectively, and gain a deeper appreciation for the beauty and power of mathematics.

How can I determine if two polynomial expressions are equivalent?

Determining if two polynomial expressions are equivalent involves several techniques, each providing a unique perspective on the concept. One of the most common methods is algebraic manipulation, which involves applying the rules of algebra to transform one expression into the other. This can include expanding, factoring, combining like terms, and using algebraic identities. For example, to determine if (x+2)(xβˆ’2)(x+2)(x-2) is equivalent to x2βˆ’4x^2 - 4, we can expand the first expression using the distributive property (FOIL method): (x+2)(xβˆ’2)=x2βˆ’2x+2xβˆ’4=x2βˆ’4(x+2)(x-2) = x^2 - 2x + 2x - 4 = x^2 - 4. Since the expanded form matches the second expression, we can conclude that they are equivalent. Another useful technique is substitution. This involves replacing the variable with specific values and checking if both expressions produce the same result. If the expressions are equivalent, they should yield the same output for any valid substitution. For example, let's substitute x=3x = 3 into both expressions: (x+2)(xβˆ’2)=(3+2)(3βˆ’2)=5(1)=5(x+2)(x-2) = (3+2)(3-2) = 5(1) = 5 and x2βˆ’4=32βˆ’4=9βˆ’4=5x^2 - 4 = 3^2 - 4 = 9 - 4 = 5. Since both expressions yield the same result, this provides evidence that they are equivalent. However, it's important to note that substitution alone does not guarantee equivalence. It's possible for two expressions to produce the same result for a specific value but not be equivalent in general. Therefore, substitution is best used in conjunction with other techniques. A third method for determining equivalence is graphical analysis. This involves plotting the graphs of the expressions and comparing them visually. If the graphs are identical, the expressions are equivalent. This method can be particularly helpful for visualizing the behavior of polynomials and understanding their relationships. For example, if we graph y=(x+2)(xβˆ’2)y = (x+2)(x-2) and y=x2βˆ’4y = x^2 - 4, we will see that the graphs are the same parabola, confirming their equivalence. In summary, determining if two polynomial expressions are equivalent involves a combination of algebraic manipulation, substitution, and graphical analysis. By using these techniques, we can gain a deeper understanding of the relationships between polynomials and solve algebraic problems more effectively.

What are some common mistakes to avoid when simplifying polynomial expressions?

When simplifying polynomial expressions, there are several common pitfalls that can lead to errors. Awareness of these mistakes is crucial for accurate algebraic manipulation. One frequent mistake is incorrectly applying the distributive property. This property states that a(b+c)=ab+aca(b + c) = ab + ac. A common error is to forget to distribute the term to every element inside the parentheses. For example, when simplifying 2(x+3)2(x + 3), some might write 2x+32x + 3 instead of the correct 2x+62x + 6. Another common mistake occurs when dealing with negative signs. For example, when simplifying βˆ’(xβˆ’4)-(x - 4), it's essential to distribute the negative sign to both terms inside the parentheses, resulting in βˆ’x+4-x + 4. A frequent error is to write βˆ’xβˆ’4-x - 4, failing to change the sign of the constant term. Combining like terms is another area where mistakes often occur. Like terms are terms that have the same variable raised to the same power. Only like terms can be combined. For example, 3x23x^2 and 5x25x^2 are like terms and can be combined to get 8x28x^2. However, 3x23x^2 and 5x5x are not like terms and cannot be combined. A common error is to mistakenly combine unlike terms, such as adding 3x23x^2 and 5x5x to get 8x38x^3 or 8x28x^2, both of which are incorrect. When squaring a binomial, such as (x+2)2(x + 2)^2, it's important to use the correct identity: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2. A common mistake is to simply square each term individually, writing (x+2)2=x2+4(x + 2)^2 = x^2 + 4, which is incorrect. The correct expansion is (x+2)2=x2+4x+4(x + 2)^2 = x^2 + 4x + 4. Another common error occurs when dealing with exponents. It's crucial to remember the rules of exponents, such as xmβˆ—xn=x(m+n)x^m * x^n = x^(m+n) and (xm)n=x(mn)(x^m)^n = x^(mn). For example, when multiplying x2x^2 by x3x^3, the correct result is x5x^5, not x6x^6. Similarly, when raising x2x^2 to the power of 3, the correct result is x6x^6, not x5x^5. By being mindful of these common mistakes and practicing algebraic manipulation carefully, you can significantly reduce errors and improve your accuracy in simplifying polynomial expressions.

What are some real-world applications of polynomial equivalence?

Polynomial equivalence isn't just an abstract mathematical concept; it has numerous real-world applications across various fields. One significant application is in engineering, particularly in circuit analysis. Electrical circuits can be modeled using polynomial equations, and understanding polynomial equivalence allows engineers to simplify these equations, making it easier to analyze the circuit's behavior and design efficient systems. For instance, equivalent circuits can be derived using polynomial manipulation, reducing the complexity of the analysis and optimizing circuit performance. In computer graphics, polynomial equations are used to represent curves and surfaces. Polynomial equivalence plays a crucial role in transforming and manipulating these shapes. For example, BΓ©zier curves, which are widely used in computer-aided design (CAD) and animation, are defined by polynomial equations. Understanding how to express these curves in equivalent forms allows graphic designers to create smooth and visually appealing shapes. Cryptography, the science of secure communication, also utilizes polynomial equivalence. Many cryptographic algorithms rely on the properties of polynomials over finite fields. Polynomial equivalence is used to simplify encryption and decryption processes, making them more efficient and secure. In particular, equivalent polynomial representations can be used to optimize the computation of cryptographic keys and messages. In physics, polynomial equations are used to model various phenomena, such as projectile motion and the behavior of waves. Simplifying these equations using polynomial equivalence can make them easier to solve and interpret. For example, the trajectory of a projectile can be described by a quadratic equation, and understanding polynomial equivalence can help in determining the range and maximum height of the projectile. Optimization problems, which arise in various fields such as economics and logistics, often involve polynomial functions. Polynomial equivalence can be used to transform these functions into forms that are easier to optimize. For example, completing the square is a technique that utilizes polynomial equivalence to find the minimum or maximum value of a quadratic function. In statistics, polynomial regression is used to model the relationship between variables. Polynomial equivalence can be used to simplify the regression equations and improve the accuracy of the model. For example, transforming the polynomial equation can help in reducing multicollinearity, a common problem in regression analysis. These are just a few examples of the many real-world applications of polynomial equivalence. By understanding this fundamental concept, we can solve complex problems in various fields and develop innovative solutions.

#repair-input-keyword: Which expression is equivalent to the polynomial (x+8)2(x+8)^2? Choices: (x+8)2(x+8)^2, (x+81)(xβˆ’81)(x+81)(x-81), (x+8i)2(x+8 i)^2, (x+16)(x+4)(x+16)(x+4). #title: Finding Equivalent Polynomial Expressions A Step-by-Step Guide