Identifying Points On A Circle A Step By Step Guide

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In the realm of geometry, the circle stands as a fundamental shape, characterized by its elegance and mathematical precision. Understanding the properties of a circle, such as its center and radius, is crucial for identifying points that lie on its circumference. In this comprehensive guide, we will delve into the intricacies of circles, exploring how to determine whether a given point resides on a circle with a specific center and radius. We will use the equation of a circle to solve the problem. To accurately identify the points on the circle, we'll delve into the foundational concept of the circle's equation, which mathematically expresses the relationship between the circle's center, radius, and any point on its circumference. This equation serves as a powerful tool for determining whether a given point lies on the circle or not. Furthermore, we will dissect the concept of distance formula, which serves as the backbone for calculating the distance between two points in a coordinate plane. This formula plays a vital role in determining whether the distance between a given point and the center of the circle matches the radius, thus confirming the point's location on the circle. By mastering the circle's equation and the distance formula, we can confidently navigate the world of circles and accurately identify the points that grace their circumference.

Understanding the Equation of a Circle

The equation of a circle is a mathematical expression that defines the relationship between the coordinates of any point on the circle and the circle's center and radius. The standard form of the equation of a circle with center (h,k)(h, k) and radius rr is given by:

(x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2

This equation stems from the Pythagorean theorem, which relates the sides of a right triangle. In the context of a circle, the distance between any point (x,y)(x, y) on the circle and the center (h,k)(h, k) is equal to the radius rr. This distance can be calculated using the distance formula, which is derived from the Pythagorean theorem.

To truly understand the equation of a circle, let's dissect its components and explore how they interact to define the circle's shape and position. The center (h,k)(h, k) serves as the circle's anchor point, dictating its location on the coordinate plane. The radius rr, on the other hand, determines the circle's size, defining the distance from the center to any point on the circumference. The variables xx and yy represent the coordinates of any point on the circle, and their relationship is governed by the equation. By plugging in the coordinates of a point into the equation, we can verify whether it lies on the circle or not. If the equation holds true, the point resides on the circle; otherwise, it lies outside the circle's boundary. The equation of a circle provides a concise and elegant way to represent the circle's properties, enabling us to perform various calculations and analyses related to circles. For instance, we can use the equation to determine the distance between two points on the circle, find the tangent line at a specific point, or calculate the area and circumference of the circle. By mastering the equation of a circle, we unlock a powerful tool for understanding and manipulating circles in the realm of geometry.

Delving into the Distance Formula

The distance formula is a fundamental tool in coordinate geometry that allows us to calculate the distance between two points in a coordinate plane. The distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

This formula is derived from the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In the context of the distance formula, the distance between the two points is the hypotenuse of a right triangle, and the differences in the x-coordinates and y-coordinates represent the lengths of the other two sides.

Let's break down the distance formula to gain a deeper understanding of its mechanics and applications. The formula involves calculating the difference between the x-coordinates and the y-coordinates of the two points, squaring these differences, adding them together, and then taking the square root of the sum. This process effectively calculates the length of the straight line segment connecting the two points, which represents the distance between them. The distance formula is a versatile tool that finds applications in various geometric problems. For instance, it can be used to determine the length of a line segment, verify if three points are collinear (lie on the same line), or calculate the perimeter of a polygon. In the context of circles, the distance formula plays a crucial role in determining whether a given point lies on the circle. By calculating the distance between the point and the center of the circle, we can compare it with the radius. If the distance equals the radius, the point resides on the circle; otherwise, it lies outside the circle's boundary. The distance formula provides a fundamental building block for geometric calculations, enabling us to quantify distances and spatial relationships between points in a coordinate plane.

Applying the Concepts to the Problem

The problem asks us to identify a point that lies on a circle with center (0,0)(0, 0) and radius 55. To solve this, we can use the equation of the circle and the distance formula. The equation of the circle with center (0,0)(0, 0) and radius 55 is:

x2+y2=52x^2 + y^2 = 5^2

x2+y2=25x^2 + y^2 = 25

Now, we can test each of the given options to see which point satisfies this equation.

Let's embark on a step-by-step journey to apply the concepts of the circle's equation and the distance formula to pinpoint the point that gracefully resides on the circumference of our designated circle. We begin by revisiting the equation of the circle, which serves as our guiding principle in this endeavor. With the center firmly anchored at the origin (0, 0) and the radius stretching out to a length of 5 units, we have established the circle's foundation. The equation x2+y2=25x^2 + y^2 = 25 encapsulates the essence of this circle, dictating the relationship between the coordinates of any point that claims membership on its circumference. Now, armed with this equation, we embark on a quest to scrutinize each of the provided options, meticulously evaluating whether they align with the circle's defining equation. This process involves substituting the coordinates of each point into the equation and observing whether the equation holds true. If the equation balances perfectly, we have unearthed a point that gracefully resides on the circle's circumference. Conversely, if the equation falters, we know that the point lies outside the circle's embrace. This methodical approach ensures that we leave no stone unturned in our pursuit of the point that truly belongs to the circle.

Option A: (3,4)(3, 4)

Substituting x=3x = 3 and y=4y = 4 into the equation, we get:

32+42=9+16=253^2 + 4^2 = 9 + 16 = 25

Since the equation holds true, the point (3,4)(3, 4) lies on the circle.

To further solidify our understanding, let's delve into the application of the distance formula to verify the location of point A. The distance formula, as we've learned, allows us to calculate the distance between two points in a coordinate plane. In this case, we're interested in determining the distance between point A (3, 4) and the circle's center (0, 0). If this distance precisely matches the circle's radius, which is 5 units, we can confidently confirm that point A resides on the circle's circumference. Applying the distance formula, we get:

d=(3−0)2+(4−0)2=32+42=9+16=25=5d = \sqrt{(3 - 0)^2 + (4 - 0)^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5

As the calculations reveal, the distance between point A and the circle's center is indeed 5 units, perfectly aligning with the circle's radius. This reinforces our earlier conclusion that point A (3, 4) is a bona fide member of the circle's circumference. The convergence of the equation of the circle and the distance formula in confirming the location of point A underscores the interconnectedness of these geometric concepts and their efficacy in solving problems related to circles.

Option B: (4,5)(4, 5)

Substituting x=4x = 4 and y=5y = 5 into the equation, we get:

42+52=16+25=414^2 + 5^2 = 16 + 25 = 41

Since 41≠2541 \ne 25, the point (4,5)(4, 5) does not lie on the circle.

Let's further analyze option B by employing the distance formula, our trusted tool for measuring the distance between two points in the coordinate plane. We aim to determine the distance between point B (4, 5) and the circle's center (0, 0). If this distance deviates from the circle's radius of 5 units, we can confidently conclude that point B lies outside the circle's embrace. Applying the distance formula, we embark on the calculation:

d=(4−0)2+(5−0)2=42+52=16+25=41≈6.4d = \sqrt{(4 - 0)^2 + (5 - 0)^2} = \sqrt{4^2 + 5^2} = \sqrt{16 + 25} = \sqrt{41} \approx 6.4

As the calculations reveal, the distance between point B and the circle's center is approximately 6.4 units, which exceeds the circle's radius of 5 units. This clearly indicates that point B (4, 5) resides outside the circle's circumference. The discrepancy between the calculated distance and the circle's radius serves as irrefutable evidence that point B does not belong to the circle. By employing the distance formula, we have gained a deeper understanding of point B's position relative to the circle, further solidifying our comprehension of geometric relationships.

Option C: (2,3)(2, 3)

Substituting x=2x = 2 and y=3y = 3 into the equation, we get:

22+32=4+9=132^2 + 3^2 = 4 + 9 = 13

Since 13≠2513 \ne 25, the point (2,3)(2, 3) does not lie on the circle.

To further examine option C, we turn to the distance formula, our reliable tool for measuring the distance between two points in the coordinate plane. Our objective is to determine the distance between point C (2, 3) and the circle's center (0, 0). If this distance deviates from the circle's radius of 5 units, we can confidently assert that point C lies outside the circle's perimeter. Applying the distance formula, we embark on the calculation:

d=(2−0)2+(3−0)2=22+32=4+9=13≈3.6d = \sqrt{(2 - 0)^2 + (3 - 0)^2} = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13} \approx 3.6

As the calculations reveal, the distance between point C and the circle's center is approximately 3.6 units, which falls short of the circle's radius of 5 units. This clearly indicates that point C (2, 3) resides within the circle's boundaries but not on its circumference. The disparity between the calculated distance and the circle's radius serves as compelling evidence that point C does not belong to the circle's edge. By employing the distance formula, we have gained a clearer understanding of point C's position relative to the circle, further solidifying our grasp of geometric concepts.

Option D: (0,0)(0, 0)

Substituting x=0x = 0 and y=0y = 0 into the equation, we get:

02+02=00^2 + 0^2 = 0

Since 0≠250 \ne 25, the point (0,0)(0, 0) does not lie on the circle. It is the center of the circle.

To further scrutinize option D, we invoke the distance formula, our trusted instrument for measuring the distance between two points in the coordinate plane. Our aim is to ascertain the distance between point D (0, 0) and the circle's center, which also resides at (0, 0). If this distance deviates from the circle's radius of 5 units, we can definitively conclude that point D does not grace the circle's circumference. Applying the distance formula, we embark on the calculation:

d=(0−0)2+(0−0)2=02+02=0=0d = \sqrt{(0 - 0)^2 + (0 - 0)^2} = \sqrt{0^2 + 0^2} = \sqrt{0} = 0

As the calculations reveal, the distance between point D and the circle's center is 0 units, which falls significantly short of the circle's radius of 5 units. This unequivocally confirms that point D (0, 0) coincides with the circle's center, residing at the very heart of the circle rather than on its circumference. The stark contrast between the calculated distance and the circle's radius serves as irrefutable evidence that point D does not belong to the circle's edge. By employing the distance formula, we have gained a profound understanding of point D's unique position within the circle, further reinforcing our comprehension of geometric relationships.

Conclusion

By applying the equation of a circle and the distance formula, we have determined that the point (3,4)(3, 4) lies on the circle with center (0,0)(0, 0) and radius 55. This exercise demonstrates the power of these mathematical tools in solving geometric problems.

In conclusion, our exploration into the realm of circles has equipped us with the knowledge and tools to confidently identify points that reside on their circumferences. By mastering the equation of a circle and the distance formula, we have gained a deeper appreciation for the elegance and precision of geometry. These concepts not only enable us to solve specific problems but also provide a foundation for further exploration into the fascinating world of geometric shapes and their properties. The ability to navigate the circle's equation and the distance formula opens doors to a multitude of geometric applications, empowering us to analyze, manipulate, and understand the spatial relationships that govern our world.