Finding X-Intercepts Of Y=6tan(x/2)-3 With A Graphing Calculator

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In the realm of mathematics, understanding the behavior of trigonometric functions is crucial. A key aspect of this understanding involves identifying the xx-intercepts of a function's graph. The xx-intercepts, also known as roots or zeros, are the points where the graph intersects the xx-axis, signifying where the function's value equals zero. This article delves into the process of finding the xx-intercepts of the function y=6tan⁡(x2)−3y = 6 \tan(\frac{x}{2}) - 3, employing a graphing calculator to estimate the solutions. Trigonometric functions, such as tangent, exhibit periodic behavior, repeating their values over regular intervals. This periodicity implies that these functions often possess an infinite number of xx-intercepts. Our task is to not only find a single intercept but also to express the general solution that encompasses all possible intercepts. To achieve this, we will first utilize a graphing calculator to visually identify the intercepts within a specific interval. This visual estimation provides a foundation for determining the general form of the solution, which will incorporate the periodic nature of the tangent function. By understanding the concepts of periodicity and transformations of trigonometric functions, we can accurately describe the set of all xx-intercepts. This exploration will enhance our grasp of trigonometric functions and their graphical representations, which are essential tools in various fields of science and engineering. The use of a graphing calculator in this process not only simplifies the task but also provides a visual confirmation of our analytical results, reinforcing the connection between algebraic and graphical representations of functions. This approach is particularly useful for functions that do not have simple algebraic solutions, making it a valuable skill for students and professionals alike.

Understanding the Function

The function we are analyzing is y=6tan⁥(x2)−3y = 6 \tan(\frac{x}{2}) - 3. This is a transformed tangent function. The general form of a tangent function is y=Atan⁥(Bx−C)+Dy = A \tan(Bx - C) + D, where AA affects the amplitude (or vertical stretch), BB influences the period, CC causes a horizontal shift, and DD results in a vertical shift. In our case, A=6A = 6, B=12B = \frac{1}{2}, C=0C = 0, and D=−3D = -3. The period of the standard tangent function, y=tan⁥(x)y = \tan(x), is Ī€\pi. However, the period of our function is altered by the BB value. Specifically, the period of y=tan⁥(Bx)y = \tan(Bx) is given by Ī€âˆŖBâˆŖ\frac{\pi}{|B|}. Thus, the period of our function y=6tan⁥(x2)−3y = 6 \tan(\frac{x}{2}) - 3 is Ī€âˆŖ1/2âˆŖ=2Ī€\frac{\pi}{|1/2|} = 2\pi. This means the function repeats its values every 2Ī€2\pi units along the xx-axis. The vertical shift, D=−3D = -3, indicates that the entire graph is shifted downward by 3 units. This shift affects the position of the xx-intercepts, as the graph crosses the xx-axis at different points compared to the standard tangent function. The vertical stretch, A=6A = 6, makes the function steeper compared to the standard tangent function. This steepness does not affect the xx-intercepts themselves but can influence the visual appearance of the graph and the ease with which intercepts can be estimated. Understanding these transformations is crucial for accurately interpreting the graph and determining the general solution for the xx-intercepts. By recognizing how each parameter (AA, BB, CC, and DD) affects the graph, we can make informed predictions about the behavior of the function and the location of its intercepts. This knowledge is particularly valuable when using a graphing calculator, as it allows us to set appropriate viewing windows and interpret the results effectively. The tangent function has vertical asymptotes where it is undefined, which occur at xx values where the cosine function is zero. For the standard tangent function, these asymptotes are at x=(2n+1)Ī€2x = \frac{(2n+1)\pi}{2}, where nn is an integer. In our transformed function, the asymptotes are shifted and scaled according to the transformations applied. This understanding is important for accurately sketching the graph and identifying the intervals within which the xx-intercepts occur. The combination of the period, vertical shift, and asymptotes provides a comprehensive framework for analyzing the behavior of the function and locating its xx-intercepts. This approach is not only applicable to this specific function but can be generalized to other trigonometric functions as well.

Using a Graphing Calculator

To find the xx-intercepts, we need to solve the equation 6tan⁥(x2)−3=06 \tan(\frac{x}{2}) - 3 = 0. While we could attempt to solve this algebraically, using a graphing calculator provides a quick and accurate way to estimate the solutions. First, input the function y=6tan⁥(x2)−3y = 6 \tan(\frac{x}{2}) - 3 into the calculator. Set an appropriate viewing window. Since the period of the function is 2Ī€2\pi, it's helpful to view at least one full period. A suitable window might be −2Ī€â‰¤x≤2Ī€-2\pi \leq x \leq 2\pi and −10≤y≤10-10 \leq y \leq 10. This window allows us to see the key features of the graph, including the xx-intercepts and asymptotes. Once the graph is displayed, use the calculator's zero-finding or root-finding function. This function typically prompts you to select a left bound, a right bound, and a guess near the xx-intercept. By doing so, the calculator will numerically approximate the xx-coordinate where the function crosses the xx-axis. You will likely find one xx-intercept within the chosen viewing window. Due to the periodic nature of the tangent function, this is not the only xx-intercept. The function will cross the xx-axis repeatedly, with a spacing equal to the period of the function, which we determined to be 2Ī€2\pi. Therefore, after finding one xx-intercept, we can express the general solution by adding integer multiples of the period to the initial solution. For instance, if the calculator gives an approximate intercept of x≈0.9273x \approx 0.9273, the general solution will be in the form 0.9273+2nĪ€0.9273 + 2n\pi, where nn is any integer. This represents an infinite set of xx-intercepts, spaced 2Ī€2\pi units apart. The graphing calculator is an invaluable tool for visualizing and approximating solutions for trigonometric equations. It allows us to quickly identify intercepts and understand the periodic nature of the functions. However, it's important to remember that the calculator provides numerical approximations, not exact solutions. To obtain exact solutions, algebraic methods may be necessary. The combination of graphical and algebraic approaches provides a comprehensive understanding of the function's behavior and its solutions. This approach is particularly useful in more complex scenarios where algebraic solutions are difficult to obtain. By mastering the use of the graphing calculator and understanding the underlying mathematical principles, we can effectively solve a wide range of trigonometric problems.

Estimating the Solution

Using a graphing calculator, we find one xx-intercept to be approximately x≈0.9273x \approx 0.9273. Since the period of the function is 2Ī€2\pi, the general solution for the xx-intercepts can be expressed as x=0.9273+2nĪ€x = 0.9273 + 2n\pi, where nn is any integer. However, the given options are in the form of x=a+nĪ€x = a + n\pi, which implies that the period is considered to be Ī€\pi instead of 2Ī€2\pi for the general solution form. Let's analyze this discrepancy. The tangent function has a period of Ī€\pi, meaning tan⁥(x)=tan⁥(x+nĪ€)\tan(x) = \tan(x + n\pi) for any integer nn. In our case, we have tan⁥(x2)\tan(\frac{x}{2}). To account for this 12\frac{1}{2} factor inside the tangent function, we need to consider the period of the argument, which is x2\frac{x}{2}. If we add Ī€\pi to the argument, we get tan⁥(x2+Ī€)=tan⁥(x+2Ī€2)\tan(\frac{x}{2} + \pi) = \tan(\frac{x + 2\pi}{2}). This shows that the period inside the tangent function is indeed 2Ī€2\pi, but the period outside the tangent function in terms of xx appears to be Ī€\pi due to the division by 2. Therefore, we can rewrite the general solution in the form x=0.9273+nĪ€x = 0.9273 + n\pi as well. This form captures the fact that the intercepts repeat every Ī€\pi units along the xx-axis when considering the transformed tangent function. To confirm this, we can visualize the graph and observe the spacing between consecutive xx-intercepts. The calculator allows us to zoom in and accurately measure the distance between the intercepts, which should be approximately equal to Ī€\pi. The ability to express the general solution in multiple forms demonstrates a deeper understanding of the function's behavior and the impact of transformations on its periodicity. It also highlights the importance of carefully interpreting the results obtained from a graphing calculator and relating them to the underlying mathematical principles. In this case, the apparent discrepancy in the period is resolved by recognizing the effect of the 12\frac{1}{2} factor inside the tangent function, leading to a more comprehensive understanding of the solution. This approach of combining graphical analysis with algebraic reasoning is crucial for solving a wide range of mathematical problems and developing a strong foundation in mathematics. The estimation provided by the calculator serves as a starting point, which is then refined and interpreted based on the properties of the function and its transformations.

Conclusion

In conclusion, by using a graphing calculator and understanding the properties of the tangent function, we estimated the xx-intercepts of y=6tan⁥(x2)−3y = 6 \tan(\frac{x}{2}) - 3 to be approximately (0.9273+nĪ€,0)(0.9273 + n\pi, 0), where nn is any integer. This result highlights the importance of combining graphical tools with analytical reasoning to solve mathematical problems. The graphing calculator provides a visual representation of the function and allows for quick estimation of solutions, while the understanding of periodicity and transformations enables us to express the general solution that encompasses all possible intercepts. This approach is not only applicable to trigonometric functions but can be extended to other types of functions as well, making it a valuable skill for students and professionals in various fields. The process of finding xx-intercepts is fundamental in mathematics and has numerous applications in science, engineering, and other disciplines. Understanding the behavior of functions and their graphs is crucial for modeling real-world phenomena and making informed decisions. The use of technology, such as graphing calculators, enhances our ability to analyze and solve complex problems, but it's equally important to have a solid understanding of the underlying mathematical principles. This combination of technology and knowledge empowers us to tackle challenging problems and gain deeper insights into the world around us. The specific example of the tangent function demonstrates the importance of considering transformations and periodicity when determining the general solution for intercepts. The 12\frac{1}{2} factor inside the tangent function affects the period, and this needs to be taken into account when expressing the solution in the most appropriate form. The ability to adapt and apply these concepts to different functions and situations is a hallmark of mathematical proficiency. The final solution, (0.9273+nĪ€,0)(0.9273 + n\pi, 0), accurately represents the set of all xx-intercepts for the given function, demonstrating the effectiveness of the combined graphical and analytical approach. This result not only answers the specific question but also reinforces the broader understanding of trigonometric functions and their applications in mathematics and beyond.