Finding The Y-intercept Of Y Equals -1/2 Cos(3/2 X)

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The yy-intercept is a fundamental concept in mathematics, especially when dealing with functions and their graphical representations. Understanding how to find the yy-intercept is crucial for analyzing and interpreting various mathematical models. In this comprehensive guide, we will delve into the process of determining the yy-intercept of the function y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x), breaking down each step to ensure clarity and a solid understanding. We will not only solve the problem at hand but also explore the underlying principles and concepts, making this a valuable resource for anyone studying trigonometric functions.

Decoding the yy-intercept

Before we dive into the specifics of the given function, let's first establish a clear understanding of what the yy-intercept represents. The yy-intercept is the point where the graph of a function intersects the yy-axis. In simpler terms, it's the yy-coordinate of the point where the graph crosses the vertical axis. This point is characterized by having an xx-coordinate of 0. Therefore, to find the yy-intercept of any function, we set x=0x = 0 and solve for yy. This seemingly simple concept is the key to unlocking a wealth of information about a function's behavior and its graphical representation.

The yy-intercept provides valuable insight into the function's behavior at the point where the input is zero. It helps us visualize the starting point of the function on the coordinate plane and can be a critical piece of information when modeling real-world phenomena. In many applications, the yy-intercept represents an initial condition or a baseline value. For instance, in a graph representing the growth of a population, the yy-intercept might represent the initial population size. Similarly, in a graph depicting the decay of a radioactive substance, the yy-intercept could represent the initial amount of the substance. Therefore, mastering the technique of finding the yy-intercept is not just a mathematical exercise but a practical skill with far-reaching implications.

Navigating the Cosine Function

The function we are dealing with, y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x), involves the cosine function, a cornerstone of trigonometry. The cosine function, denoted as cos⁑(x)\cos(x), is a periodic function that oscillates between -1 and 1. Its graph is a wave-like curve that repeats itself every 2Ο€2\pi radians. Understanding the basic properties of the cosine function is essential for determining the yy-intercept of our given function. The standard cosine function, y=cos⁑(x)y = \cos(x), has a yy-intercept at the point (0, 1). This is because the cosine of 0 radians is equal to 1. However, our function is a modified version of the standard cosine function, with a vertical compression and a horizontal scaling, which will affect the yy-intercept.

The vertical compression is introduced by the coefficient βˆ’12-\frac{1}{2} in front of the cosine function. This coefficient scales the output of the cosine function by a factor of βˆ’12-\frac{1}{2}. In other words, it compresses the graph vertically and reflects it across the xx-axis. The horizontal scaling is introduced by the factor 32\frac{3}{2} inside the cosine function. This factor affects the period of the cosine function, which is the length of one complete cycle. The period of the standard cosine function is 2Ο€2\pi, but the period of our function is given by 2Ο€32=4Ο€3\frac{2\pi}{\frac{3}{2}} = \frac{4\pi}{3}. While the horizontal scaling affects the period and the xx-intercepts, it does not directly influence the yy-intercept. The yy-intercept is solely determined by the vertical scaling and the value of the cosine function at x=0x = 0.

The yy-intercept Calculation

Now that we have a firm grasp of the underlying concepts, let's proceed with the calculation of the yy-intercept for the function y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x). As we discussed earlier, to find the yy-intercept, we need to set x=0x = 0 and solve for yy. Substituting x=0x = 0 into the function, we get:

y=βˆ’12cos⁑(32β‹…0)y = -\frac{1}{2} \cos(\frac{3}{2} \cdot 0)

Simplifying the expression inside the cosine function:

y=βˆ’12cos⁑(0)y = -\frac{1}{2} \cos(0)

We know that the cosine of 0 radians is 1, so:

y=βˆ’12β‹…1y = -\frac{1}{2} \cdot 1

Finally, we get:

y=βˆ’12y = -\frac{1}{2}

Therefore, the yy-intercept of the function y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x) is βˆ’12-\frac{1}{2}. This means that the graph of the function intersects the yy-axis at the point (0,βˆ’12)(0, -\frac{1}{2}). This point represents the value of the function when the input xx is zero. In the context of a graph, it's the point where the curve crosses the vertical axis. This simple calculation is a powerful tool for understanding the behavior of the function and visualizing its graph.

Selecting the Correct Option

Having calculated the yy-intercept, we can now confidently identify the correct option from the given choices. The options provided are:

A. (βˆ’12,0)\left(-\frac{1}{2}, 0\right) B. (0,βˆ’12)\left(0, -\frac{1}{2}\right) C. (0,32)\left(0, \frac{3}{2}\right) D. (32,0)\left(\frac{3}{2}, 0\right)

Recall that the yy-intercept is a point on the coordinate plane, represented as (x,y)(x, y). We found that the yy-intercept occurs when x=0x = 0 and y=βˆ’12y = -\frac{1}{2}. Therefore, the correct point representing the yy-intercept is (0,βˆ’12)(0, -\frac{1}{2}). Comparing this with the given options, we can see that option B, (0,βˆ’12)\left(0, -\frac{1}{2}\right), matches our calculated yy-intercept. The other options represent different points on the coordinate plane and do not correspond to the yy-intercept of the given function. Option A, (βˆ’12,0)\left(-\frac{1}{2}, 0\right), represents the xx-intercept, which is the point where the graph intersects the xx-axis. Options C and D do not have any direct significance in the context of the yy-intercept.

Therefore, the correct answer is B. (0,βˆ’12)\left(0, -\frac{1}{2}\right). This confirms that our calculations and understanding of the yy-intercept are accurate. The ability to correctly identify the yy-intercept is a crucial skill in mathematics, allowing for a deeper understanding of functions and their graphical representations.

Expanding the Horizon: Beyond the yy-intercept

While finding the yy-intercept is a significant step in understanding a function, it's just one piece of the puzzle. To gain a comprehensive understanding of a function, we need to explore other key features, such as the xx-intercepts, the period, the amplitude, and the phase shift. The xx-intercepts are the points where the graph intersects the xx-axis, and they are found by setting y=0y = 0 and solving for xx. The period of a trigonometric function is the length of one complete cycle, and it determines how often the function repeats itself. The amplitude is the vertical distance between the midline and the maximum or minimum value of the function. The phase shift is a horizontal shift of the graph, which can be introduced by adding or subtracting a constant from the input variable.

In the case of the function y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x), we have already found the yy-intercept. To find the xx-intercepts, we would set y=0y = 0 and solve for xx. The period of the function is 4Ο€3\frac{4\pi}{3}, as we discussed earlier. The amplitude of the function is |- rac{1}{2}| = \frac{1}{2}, which represents the maximum deviation of the function from the xx-axis. There is no phase shift in this function, as there is no constant added or subtracted from the input variable xx. By analyzing these features in addition to the yy-intercept, we can create a detailed sketch of the graph and gain a thorough understanding of the function's behavior. This holistic approach to function analysis is essential for solving complex mathematical problems and applying mathematical concepts to real-world scenarios.

Conclusion

In this comprehensive guide, we have successfully determined the yy-intercept of the function y=βˆ’12cos⁑(32x)y = -\frac{1}{2} \cos(\frac{3}{2}x). We began by establishing a clear understanding of the yy-intercept and its significance in the context of functions and their graphs. We then delved into the properties of the cosine function and how transformations such as vertical compression and horizontal scaling affect its behavior. By setting x=0x = 0 and solving for yy, we calculated the yy-intercept to be βˆ’12-\frac{1}{2}, which corresponds to the point (0,βˆ’12)(0, -\frac{1}{2}). This allowed us to confidently select the correct option from the given choices. Furthermore, we expanded our discussion to encompass other key features of functions, such as xx-intercepts, period, amplitude, and phase shift, emphasizing the importance of a holistic approach to function analysis. Mastering the technique of finding the yy-intercept, along with these other features, is a crucial step in developing a strong foundation in mathematics and its applications.