Finding The Radius Of A Circle X² + Y² - 2x + 8y - 47 = 0

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In the realm of mathematics, circles hold a fundamental position, gracing the landscapes of geometry, trigonometry, and calculus alike. Their elegant symmetry and consistent properties make them essential building blocks for more complex mathematical structures and real-world applications. Central to understanding circles is the ability to decipher their equations, extracting key information such as their center and, of course, their radius. This article delves into the process of finding the radius of a circle given its equation in general form, specifically focusing on the equation x² + y² - 2x + 8y - 47 = 0. By mastering this technique, you'll unlock a deeper appreciation for the relationship between algebraic expressions and geometric shapes.

Understanding the General Equation of a Circle

Before we embark on solving our specific problem, let's lay a solid foundation by reviewing the general equation of a circle. This equation, a cornerstone of analytic geometry, provides a powerful tool for representing circles on the Cartesian plane. The general form of the equation is expressed as:

x² + y² + Dx + Ey + F = 0

Where:

  • x and y are the coordinates of any point on the circle's circumference.
  • D and E are coefficients that relate to the circle's center.
  • F is a constant term that, along with D and E, determines the circle's radius.

This general form, while comprehensive, doesn't immediately reveal the circle's center or radius. To extract this information, we need to transform the equation into its standard form, also known as the center-radius form. This transformation involves a clever technique called completing the square.

Transforming to Standard Form: Completing the Square

Completing the square is an algebraic method that allows us to rewrite quadratic expressions in a more revealing form. In the context of circle equations, it enables us to convert the general form into the standard form, which directly displays the circle's center and radius. The standard form of the equation of a circle is:

(x - h)² + (y - k)² = r²

Where:

  • (h, k) represents the coordinates of the circle's center.
  • r denotes the circle's radius.

To transform the general equation into this standard form, we follow these steps:

  1. Group x terms and y terms: Rearrange the general equation to group the x terms together and the y terms together. This sets the stage for completing the square separately for both variables.
  2. Complete the square for x: Take half of the coefficient of the x term (D/2), square it ((D/2)²), and add it to both sides of the equation. This creates a perfect square trinomial on the left side involving the x terms.
  3. Complete the square for y: Similarly, take half of the coefficient of the y term (E/2), square it ((E/2)²), and add it to both sides of the equation. This creates a perfect square trinomial on the left side involving the y terms.
  4. Rewrite as squared terms: Express the perfect square trinomials as squared binomials. For example, x² + Dx + (D/2)² can be rewritten as (x + D/2)². Do the same for the y terms.
  5. Isolate the constant term: Move the constant terms to the right side of the equation. The right side will now represent r², the square of the radius.

By meticulously following these steps, we can transform the general equation of a circle into its standard form, unveiling the circle's center and radius with clarity.

Applying the Technique to Our Equation: x² + y² - 2x + 8y - 47 = 0

Now, let's put our knowledge into practice by finding the radius of the circle defined by the equation x² + y² - 2x + 8y - 47 = 0. We'll systematically apply the steps of completing the square to transform this equation into standard form.

  1. Group x terms and y terms:

    Begin by rearranging the equation to group the x terms and y terms together:

    (x² - 2x) + (y² + 8y) = 47

    We've moved the constant term to the right side to prepare for completing the square.

  2. Complete the square for x:

    Take half of the coefficient of the x term (-2), which is -1. Square it to get (-1)² = 1. Add 1 to both sides of the equation:

    (x² - 2x + 1) + (y² + 8y) = 47 + 1

    We've added 1 to both sides to maintain the equation's balance.

  3. Complete the square for y:

    Take half of the coefficient of the y term (8), which is 4. Square it to get 4² = 16. Add 16 to both sides of the equation:

    (x² - 2x + 1) + (y² + 8y + 16) = 47 + 1 + 16

    Again, we've added 16 to both sides to preserve equality.

  4. Rewrite as squared terms:

    Rewrite the perfect square trinomials as squared binomials:

    (x - 1)² + (y + 4)² = 64

    Now, the equation is in standard form!

  5. Identify the radius:

    Comparing our equation to the standard form (x - h)² + (y - k)² = r², we see that r² = 64. Taking the square root of both sides, we get r = 8.

Therefore, the radius of the circle defined by the equation x² + y² - 2x + 8y - 47 = 0 is 8 units.

The Radius: Unveiling the Circle's Size

The radius, a fundamental property of a circle, quantifies its size. It represents the distance from the center of the circle to any point on its circumference. In the context of our equation, we've successfully extracted the radius by transforming the equation into standard form. The radius, in essence, dictates how "wide" or "compact" the circle is.

A larger radius signifies a larger circle, with points on the circumference further away from the center. Conversely, a smaller radius indicates a smaller circle, with points on the circumference closer to the center. The radius, therefore, provides a direct measure of the circle's extent in the plane.

Understanding the radius is crucial for various applications, from calculating the circle's area and circumference to analyzing its interactions with other geometric shapes. In engineering, architecture, and design, the radius plays a critical role in determining the dimensions and spatial relationships of circular components.

Beyond the Radius: Exploring the Circle's Center

While our primary focus has been on finding the radius, the standard form of the circle equation also provides valuable information about the circle's center. The center, denoted by the coordinates (h, k) in the standard form (x - h)² + (y - k)² = r², represents the circle's central point of symmetry.

In our example, the standard form equation (x - 1)² + (y + 4)² = 64 reveals that the center of the circle is located at the point (1, -4). This means that the circle is centered 1 unit to the right of the y-axis and 4 units below the x-axis.

The center and radius together completely define a circle's position and size in the plane. Knowing both allows us to accurately plot the circle and analyze its relationships with other geometric figures.

Applications in the Real World: Circles in Action

The study of circles isn't confined to the abstract realm of mathematics; circles permeate the real world, appearing in countless applications across diverse fields. From the wheels that propel our vehicles to the lenses that focus our vision, circles play a fundamental role in our daily lives.

  • Engineering: Circles are essential components in gears, pulleys, and rotating machinery. Their uniform shape ensures smooth and efficient motion transmission.
  • Architecture: Circular designs often feature in buildings, bridges, and domes, offering structural stability and aesthetic appeal.
  • Physics: Circular motion is a fundamental concept in physics, governing the orbits of planets, the rotation of objects, and the behavior of waves.
  • Computer Graphics: Circles are basic building blocks in computer graphics, used to create a wide range of shapes and patterns.
  • Navigation: The Earth's spherical shape necessitates the use of circles in navigation, with latitude and longitude lines forming circular grids on the globe.

These are just a few examples of the many ways circles manifest in the real world. Their ubiquity underscores the importance of understanding their properties and equations.

Conclusion: Mastering the Circle Equation

In this comprehensive exploration, we've delved into the process of finding the radius of a circle given its equation in general form. By mastering the technique of completing the square, we can transform the general equation into the standard form, unveiling the circle's center and radius with ease. The radius, a fundamental property, quantifies the circle's size, while the center pinpoints its location in the plane.

Our journey extended beyond the mathematical mechanics, highlighting the real-world applications of circles across various fields. From engineering to architecture to physics, circles play a vital role in shaping our world.

By understanding the circle equation and its implications, you've equipped yourself with a powerful tool for navigating the mathematical landscape and appreciating the geometric harmony that surrounds us. Keep exploring, keep questioning, and keep unraveling the fascinating world of mathematics!