Finding The Original Expression Simplified To 1/256 T^28

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Introduction: The Quest for the Original Expression

In the realm of algebra, simplification is a fundamental process. It allows us to transform complex expressions into more manageable and understandable forms. When we encounter a simplified expression like 1256t28\frac{1}{256} t^{28}, it naturally piques our curiosity. What was the original expression that, after simplification, resulted in this elegant form? This article delves into the process of identifying the expression that simplifies to 1256t28\frac{1}{256} t^{28}, exploring the underlying mathematical principles and techniques involved.

This problem is a fascinating exercise in reverse engineering mathematical expressions. We're presented with the final, simplified result and tasked with finding the initial form. This involves understanding the rules of exponents, the order of operations, and how these rules interact during simplification. By carefully analyzing the given options and applying our knowledge of mathematical principles, we can unravel the mystery and identify the expression that, through the process of simplification, leads to 1256t28\frac{1}{256} t^{28}.

In essence, we are acting as mathematical detectives, tracing the steps backward to uncover the original expression. This process not only reinforces our understanding of algebraic manipulation but also sharpens our problem-solving skills. The challenge lies in recognizing the patterns and applying the correct rules to navigate from the simplified form back to its original state. So, let's embark on this mathematical journey and discover the expression that holds the key to this simplification puzzle.

Dissecting the Simplified Form: 1256t28\frac{1}{256} t^{28}

To begin our quest, we must first dissect the simplified form, 1256t28\frac{1}{256} t^{28}, and understand its components. This expression consists of two primary parts: a numerical coefficient, 1256\frac{1}{256}, and a variable term, t28t^{28}. The coefficient represents a constant value, while the variable term indicates a variable, tt, raised to the power of 28.

Analyzing the Numerical Coefficient: The coefficient 1256\frac{1}{256} is a fraction, indicating that the original expression likely involved division or a negative exponent. We can further break down 256 as a power of 4 or 2. Specifically, 256=44=28256 = 4^4 = 2^8. This understanding is crucial as we examine the options, as the base of the exponent in the original expression will likely be either 4 or 2.

Examining the Variable Term: The variable term t28t^{28} tells us that the variable tt was raised to the power of 28 after simplification. This exponent of 28 could have resulted from various operations, such as multiplying exponents, dividing exponents, or raising a power to another power. We need to consider these possibilities as we analyze the given options.

Connecting the Pieces: Now, we need to consider how the coefficient and the variable term might have been connected in the original expression. The fact that the coefficient is a fraction and the variable term has a positive exponent suggests that the original expression may have involved negative exponents that were manipulated during simplification. The exponent of 28 also hints at the possibility of raising a power of tt to another power, as 28 can be factored into products like 4 * 7 or 2 * 14.

By carefully dissecting the simplified form, we have gained valuable insights into the possible structure of the original expression. We have identified key clues, such as the fractional coefficient, the power of 256, and the exponent of 28, which will guide us as we evaluate the options and determine the expression that simplifies to 1256t28\frac{1}{256} t^{28}. This detailed analysis provides a solid foundation for our investigation and sets us on the right path to solving the puzzle.

Evaluating the Options: A. (256t−7)4\left(256 t^{-7}\right)^4

Let's begin our evaluation with option A: (256t−7)4\left(256 t^{-7}\right)^4. To determine if this expression simplifies to 1256t28\frac{1}{256} t^{28}, we need to apply the rules of exponents and simplify it step by step.

Step 1: Apply the Power of a Product Rule: The power of a product rule states that (ab)n=anbn(ab)^n = a^n b^n. Applying this rule to our expression, we get:

(256t−7)4=2564⋅(t−7)4\left(256 t^{-7}\right)^4 = 256^4 \cdot (t^{-7})^4

Step 2: Simplify the Numerical Term: We know that 256=28256 = 2^8, so 2564=(28)4256^4 = (2^8)^4. Applying the power of a power rule, which states that (am)n=amn(a^m)^n = a^{mn}, we get:

2564=(28)4=232256^4 = (2^8)^4 = 2^{32}

Step 3: Simplify the Variable Term: Applying the power of a power rule to the variable term, we get:

(t−7)4=t−7⋅4=t−28(t^{-7})^4 = t^{-7 \cdot 4} = t^{-28}

Step 4: Combine the Terms: Now, we combine the simplified numerical and variable terms:

2564⋅(t−7)4=232t−28256^4 \cdot (t^{-7})^4 = 2^{32} t^{-28}

Step 5: Express the Result: The result, 232t−282^{32} t^{-28}, is clearly not equal to 1256t28\frac{1}{256} t^{28}. The numerical coefficient is a large positive power of 2, and the exponent of tt is -28, not 28. Therefore, option A is not the correct answer.

Conclusion for Option A: After careful simplification, we have shown that (256t−7)4\left(256 t^{-7}\right)^4 does not simplify to 1256t28\frac{1}{256} t^{28}. The resulting expression has a very large numerical coefficient and a negative exponent for tt, which are inconsistent with the target simplified form. This eliminates option A from our list of potential solutions.

Evaluating the Options: B. (4t28)−4\left(4 t^{28}\right)^{-4}

Next, let's analyze option B: (4t28)−4\left(4 t^{28}\right)^{-4}. Similar to option A, we will simplify this expression using the rules of exponents to see if it matches our target simplified form of 1256t28\frac{1}{256} t^{28}.

Step 1: Apply the Power of a Product Rule: Using the rule (ab)n=anbn(ab)^n = a^n b^n, we get:

(4t28)−4=4−4⋅(t28)−4\left(4 t^{28}\right)^{-4} = 4^{-4} \cdot (t^{28})^{-4}

Step 2: Simplify the Numerical Term: We know that 4=224 = 2^2, so 4−4=(22)−44^{-4} = (2^2)^{-4}. Applying the power of a power rule, we have:

4−4=(22)−4=2−84^{-4} = (2^2)^{-4} = 2^{-8}

Step 3: Simplify the Variable Term: Applying the power of a power rule to the variable term, we get:

(t28)−4=t28⋅(−4)=t−112(t^{28})^{-4} = t^{28 \cdot (-4)} = t^{-112}

Step 4: Combine the Terms: Now, we combine the simplified numerical and variable terms:

4−4⋅(t28)−4=2−8t−1124^{-4} \cdot (t^{28})^{-4} = 2^{-8} t^{-112}

Step 5: Express the Result: We can rewrite 2−82^{-8} as 128\frac{1}{2^8}, and since 28=2562^8 = 256, we have:

2−8t−112=1256t−1122^{-8} t^{-112} = \frac{1}{256} t^{-112}

Conclusion for Option B: The simplified form of (4t28)−4\left(4 t^{28}\right)^{-4} is 1256t−112\frac{1}{256} t^{-112}. While the numerical coefficient matches our target simplified form, the exponent of tt is -112, not 28. Therefore, option B is also not the correct answer.

Evaluating the Options: C. (256t−7)−4\left(256 t^{-7}\right)^{-4}

Now, let's examine option C: (256t−7)−4\left(256 t^{-7}\right)^{-4}. Our goal is to simplify this expression and determine if it matches our target simplified form of 1256t28\frac{1}{256} t^{28}.

Step 1: Apply the Power of a Product Rule: Using the rule (ab)n=anbn(ab)^n = a^n b^n, we get:

(256t−7)−4=256−4⋅(t−7)−4\left(256 t^{-7}\right)^{-4} = 256^{-4} \cdot (t^{-7})^{-4}

Step 2: Simplify the Numerical Term: We know that 256=28256 = 2^8, so 256−4=(28)−4256^{-4} = (2^8)^{-4}. Applying the power of a power rule, we have:

256−4=(28)−4=2−32256^{-4} = (2^8)^{-4} = 2^{-32}

Step 3: Simplify the Variable Term: Applying the power of a power rule to the variable term, we get:

(t−7)−4=t−7⋅(−4)=t28(t^{-7})^{-4} = t^{-7 \cdot (-4)} = t^{28}

Step 4: Combine the Terms: Now, we combine the simplified numerical and variable terms:

256−4⋅(t−7)−4=2−32t28256^{-4} \cdot (t^{-7})^{-4} = 2^{-32} t^{28}

Step 5: Express the Result: We can rewrite 2−322^{-32} as 1232\frac{1}{2^{32}}. Since 2322^{32} is not equal to 256, this expression does not simplify to our target form. Therefore, option C is not the correct answer.

Conclusion for Option C: The simplification of (256t−7)−4\left(256 t^{-7}\right)^{-4} yields 2−32t282^{-32} t^{28}, which does not match the target simplified form of 1256t28\frac{1}{256} t^{28}. The numerical coefficient is significantly different, making option C an incorrect choice.

Evaluating the Options: D. (4t−7)−4\left(4 t^{-7}\right)^{-4}

Finally, let's evaluate option D: (4t−7)−4\left(4 t^{-7}\right)^{-4}. We will simplify this expression using the rules of exponents to see if it simplifies to 1256t28\frac{1}{256} t^{28}.

Step 1: Apply the Power of a Product Rule: Using the rule (ab)n=anbn(ab)^n = a^n b^n, we get:

(4t−7)−4=4−4⋅(t−7)−4\left(4 t^{-7}\right)^{-4} = 4^{-4} \cdot (t^{-7})^{-4}

Step 2: Simplify the Numerical Term: We know that 4=224 = 2^2, so 4−4=(22)−44^{-4} = (2^2)^{-4}. Applying the power of a power rule, we have:

4−4=(22)−4=2−84^{-4} = (2^2)^{-4} = 2^{-8}

Since 28=2562^8 = 256, we can rewrite this as:

2−8=128=12562^{-8} = \frac{1}{2^8} = \frac{1}{256}

Step 3: Simplify the Variable Term: Applying the power of a power rule to the variable term, we get:

(t−7)−4=t−7⋅(−4)=t28(t^{-7})^{-4} = t^{-7 \cdot (-4)} = t^{28}

Step 4: Combine the Terms: Now, we combine the simplified numerical and variable terms:

4−4⋅(t−7)−4=1256t284^{-4} \cdot (t^{-7})^{-4} = \frac{1}{256} t^{28}

Step 5: Express the Result: The simplified expression is 1256t28\frac{1}{256} t^{28}, which exactly matches our target simplified form.

Conclusion for Option D: Through the process of simplification, we have confirmed that (4t−7)−4\left(4 t^{-7}\right)^{-4} indeed simplifies to 1256t28\frac{1}{256} t^{28}. This makes option D the correct answer.

Conclusion: The Original Expression Revealed

After a thorough evaluation of all the options, we have successfully identified the expression that simplifies to 1256t28\frac{1}{256} t^{28}. Our journey involved dissecting the simplified form, applying the rules of exponents, and systematically simplifying each option. Through this process, we have arrived at the solution.

The correct expression is D. (4t−7)−4\left(4 t^{-7}\right)^{-4}. This expression, when simplified using the power of a product rule and the power of a power rule, yields the target simplified form of 1256t28\frac{1}{256} t^{28}.

This problem highlights the importance of understanding and applying the rules of exponents in algebraic simplification. It also demonstrates the power of reverse engineering mathematical expressions, where we start with the simplified form and work backward to find the original form. This approach not only reinforces our algebraic skills but also enhances our problem-solving abilities.

By carefully analyzing the components of the simplified expression and systematically evaluating each option, we were able to unravel the mystery and identify the correct answer. This exercise serves as a valuable lesson in mathematical reasoning and the application of fundamental algebraic principles.