Evaluating 10^0 * X^-3 When X Is 5

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Introduction

In the realm of mathematics, evaluating expressions is a fundamental skill. This article will delve into the process of evaluating the expression 100⋅x−310^0 \cdot x^{-3} when x=5x = 5. We will break down the expression, understand the underlying mathematical principles, and step-by-step guide the reader through the evaluation process. We will also explore the concepts of exponents, particularly zero exponents and negative exponents, which are crucial for solving this problem. This comprehensive guide aims to provide a clear and concise understanding of the evaluation, ensuring that the reader can confidently tackle similar mathematical problems in the future. By understanding the order of operations and the properties of exponents, we can efficiently simplify and evaluate complex expressions. Our goal is to not only provide the solution but also to enhance the reader's overall mathematical comprehension and problem-solving skills. Let's embark on this mathematical journey together and unravel the intricacies of this expression.

Understanding Exponents

To effectively evaluate the expression, it's crucial to grasp the concept of exponents. An exponent indicates how many times a base number is multiplied by itself. For instance, in the expression ana^n, 'a' is the base, and 'n' is the exponent. This means 'a' is multiplied by itself 'n' times. When dealing with exponents, there are specific rules that govern their behavior, particularly when the exponent is zero or negative. A zero exponent, as seen in our expression with 10010^0, has a unique property. Any non-zero number raised to the power of zero equals 1. This is a fundamental rule that simplifies many mathematical expressions. In the case of negative exponents, such as x−3x^{-3}, the negative sign indicates a reciprocal. Specifically, x−nx^{-n} is equivalent to 1xn\frac{1}{x^n}. This understanding is critical for correctly evaluating expressions with negative exponents. These rules of exponents are not just abstract concepts; they are tools that allow us to manipulate and simplify complex expressions, making them easier to understand and solve. Mastering these concepts is essential for any aspiring mathematician or anyone who wants to improve their problem-solving skills in various fields that rely on mathematical principles.

Breaking Down the Expression

The expression we aim to evaluate is 100⋅x−310^0 \cdot x^{-3}. This expression consists of two main parts: 10010^0 and x−3x^{-3}, which are multiplied together. As discussed earlier, we know that any non-zero number raised to the power of zero is equal to 1. Therefore, 10010^0 simplifies to 1. The second part of the expression, x−3x^{-3}, involves a variable raised to a negative exponent. A negative exponent signifies the reciprocal of the base raised to the positive value of the exponent. In other words, x−3x^{-3} is equivalent to 1x3\frac{1}{x^3}. This understanding is crucial because it allows us to transform the expression into a more manageable form. By breaking down the expression into its components and applying the rules of exponents, we can see that the original problem can be simplified. This simplification process is a key strategy in mathematics, as it allows us to tackle complex problems by breaking them down into smaller, more easily solvable parts. Once we have simplified the expression in this way, we can proceed to substitute the given value of xx and complete the evaluation.

Substituting the Value of x

Now that we have simplified the expression to 1â‹…1x31 \cdot \frac{1}{x^3}, the next step is to substitute the given value of xx, which is 5. This means we replace the variable xx with the number 5 in our simplified expression. This substitution transforms the expression into a purely numerical one, which we can then evaluate. After substituting, the expression becomes 1â‹…1531 \cdot \frac{1}{5^3}. This step is crucial because it bridges the gap between the abstract algebraic expression and a concrete numerical value. It is a fundamental technique in algebra, allowing us to find specific solutions for equations and expressions when given certain conditions. By performing this substitution, we are essentially applying the general rule represented by the expression to a specific case, which is when xx equals 5. This process of substitution is a cornerstone of mathematical problem-solving, and mastering it is essential for success in more advanced mathematical topics.

Evaluating the Expression

With the substitution complete, our expression now reads 1â‹…1531 \cdot \frac{1}{5^3}. The next step is to evaluate the exponent. The term 535^3 means 5 multiplied by itself three times, which is 5â‹…5â‹…55 \cdot 5 \cdot 5. This calculation yields a result of 125. Therefore, our expression further simplifies to 1â‹…11251 \cdot \frac{1}{125}. Now, we simply need to perform the multiplication. Multiplying 1 by any number does not change the value of that number. So, 1â‹…11251 \cdot \frac{1}{125} equals 1125\frac{1}{125}. This fraction represents the final value of the expression when xx is 5. The process of evaluating the expression involves a sequence of steps, each building upon the previous one. By carefully following these steps and applying the rules of mathematics, we arrive at a precise and accurate solution. This demonstrates the power of mathematical principles in providing us with the tools to solve complex problems in a systematic and logical manner.

Final Answer

Therefore, after carefully evaluating the expression 100⋅x−310^0 \cdot x^{-3} when x=5x = 5, we arrive at the final answer of 1125\frac{1}{125}. This result is obtained by first simplifying the expression using the properties of exponents, then substituting the given value of xx, and finally performing the arithmetic calculations. This process showcases the importance of understanding fundamental mathematical rules and applying them systematically to solve problems. The journey from the initial expression to the final answer involves several key steps, including recognizing the zero exponent, understanding negative exponents, performing substitution, and carrying out arithmetic operations. Each step plays a crucial role in arriving at the correct solution. By mastering these steps, one can confidently tackle similar mathematical problems and gain a deeper appreciation for the power and elegance of mathematics. The final answer, 1125\frac{1}{125}, is not just a numerical result; it is the culmination of a logical and systematic process of problem-solving.