Evaluate 16^(1/2) * 2^(-3) Expressed As A Fraction

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In this comprehensive guide, we will delve into the step-by-step evaluation of the mathematical expression 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3}. Our primary objective is to express the final result as a fraction in its simplest form. This process involves understanding the principles of exponents, fractional powers, and negative exponents. By breaking down the problem into manageable steps, we aim to provide a clear and concise explanation that will benefit both students and mathematics enthusiasts. This article is meticulously crafted to enhance your understanding of exponent manipulation and simplification techniques. Let's embark on this mathematical journey together!

Understanding the Fundamentals of Exponents

Before we dive into the intricacies of evaluating 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3}, it's crucial to establish a solid foundation in the fundamentals of exponents. Exponents represent a shorthand notation for repeated multiplication. For instance, ana^n signifies the multiplication of 'a' by itself 'n' times. Here, 'a' is referred to as the base, and 'n' is the exponent or power. A firm grasp of these principles is essential for simplifying complex expressions. Understanding exponents is the cornerstone of our mathematical exploration. Let's consider some basic rules that govern exponents:

  1. Product of Powers: When multiplying two exponential terms with the same base, we add their exponents. Mathematically, this is expressed as amร—an=am+na^m \times a^n = a^{m+n}.
  2. Quotient of Powers: When dividing two exponential terms with the same base, we subtract their exponents. This rule is represented as aman=amโˆ’n\frac{a^m}{a^n} = a^{m-n}.
  3. Power of a Power: When raising an exponential term to another power, we multiply the exponents. This is denoted as (am)n=amร—n(a^m)^n = a^{m \times n}.
  4. Negative Exponents: A negative exponent indicates the reciprocal of the base raised to the positive exponent. Thus, aโˆ’n=1ana^{-n} = \frac{1}{a^n}.
  5. Fractional Exponents: A fractional exponent represents a root. Specifically, a1na^{\frac{1}{n}} is the nth root of 'a'. For example, a12a^{\frac{1}{2}} is the square root of 'a', and a13a^{\frac{1}{3}} is the cube root of 'a'.

These fundamental rules form the bedrock of exponent manipulation and will be instrumental in simplifying the expression at hand. Mastering these concepts will not only aid in solving the current problem but will also prove invaluable in tackling a wide array of mathematical challenges. The ability to fluently apply these rules is key to success in algebra and beyond. Exponent rules are crucial for simplifying complex equations. They provide a structured approach to handling expressions involving powers, roots, and reciprocals. Without a thorough understanding of these rules, manipulating and simplifying expressions like 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3} becomes significantly more challenging. Therefore, dedicating time to mastering these fundamentals is a worthwhile investment in your mathematical journey. Let's now apply these principles to the specific problem we are addressing.

Step-by-Step Evaluation of 161216^{\frac{1}{2}}

The first part of our expression is 161216^{\frac{1}{2}}. To evaluate this, we need to understand that a fractional exponent of 12\frac{1}{2} represents the square root. Therefore, 161216^{\frac{1}{2}} is the square root of 16. Finding the square root of a number involves determining a value that, when multiplied by itself, equals the original number. In this case, we are looking for a number that, when multiplied by itself, yields 16. Evaluating fractional exponents is a crucial skill in simplifying expressions. We know that 4ร—4=164 \times 4 = 16, so the square root of 16 is 4. Thus, we can simplify 161216^{\frac{1}{2}} to 4. This step is fundamental to the overall solution and showcases the application of fractional exponents. Let's break this down further to ensure complete clarity:

  • Understanding the Square Root: The square root of a number 'x' is a value 'y' such that yร—y=xy \times y = x. In mathematical notation, this is represented as x=y\sqrt{x} = y.
  • Applying to Our Problem: In our case, x=16x = 16, and we are seeking 'y' such that yร—y=16y \times y = 16.
  • Finding the Solution: By trial and error or through knowledge of multiplication tables, we find that 4ร—4=164 \times 4 = 16. Therefore, y=4y = 4.
  • Expressing the Result: Consequently, 1612=416^{\frac{1}{2}} = 4.

This detailed explanation underscores the simplicity and directness of evaluating fractional exponents when they represent common roots like the square root. This skill is not only vital for solving this particular problem but also forms a basis for more complex calculations involving roots and exponents. The ability to quickly identify and calculate square roots is an invaluable asset in mathematics. Simplifying expressions with roots becomes much easier with practice and a firm understanding of the underlying principles. Now that we have evaluated 161216^{\frac{1}{2}}, let's move on to the next part of the expression, which involves a negative exponent.

Handling the Negative Exponent: 2โˆ’32^{-3}

Now, let's address the second part of our expression: 2โˆ’32^{-3}. The presence of a negative exponent indicates that we need to take the reciprocal of the base raised to the positive exponent. In simpler terms, 2โˆ’32^{-3} is equivalent to 123\frac{1}{2^3}. This concept is crucial for understanding and simplifying expressions with negative exponents. Negative exponents signify the inverse of the base raised to the positive power. To proceed, we need to evaluate 232^3. This means multiplying 2 by itself three times: 2ร—2ร—22 \times 2 \times 2. Let's break down this calculation:

  • Understanding the Negative Exponent Rule: The rule states that aโˆ’n=1ana^{-n} = \frac{1}{a^n}.
  • Applying to Our Problem: In our case, a=2a = 2 and n=3n = 3. Therefore, 2โˆ’3=1232^{-3} = \frac{1}{2^3}.
  • Evaluating 232^3: This means 2ร—2ร—22 \times 2 \times 2.
  • Step-by-Step Calculation:
    • 2ร—2=42 \times 2 = 4
    • 4ร—2=84 \times 2 = 8
  • Expressing the Result: So, 23=82^3 = 8.
  • Substituting Back: Therefore, 2โˆ’3=182^{-3} = \frac{1}{8}.

This detailed breakdown clarifies the process of handling negative exponents and calculating the resulting value. By understanding the reciprocal relationship, we can effectively simplify expressions with negative powers. This skill is fundamental in algebra and is frequently encountered in various mathematical contexts. Mastering negative exponents is essential for success in mathematical problem-solving. The ability to quickly and accurately convert negative exponents into their reciprocal forms is a valuable asset. Now that we have evaluated 2โˆ’32^{-3} as 18\frac{1}{8}, we can combine this result with our previous evaluation of 161216^{\frac{1}{2}} to find the final answer.

Combining the Results: 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3}

Having evaluated 161216^{\frac{1}{2}} as 4 and 2โˆ’32^{-3} as 18\frac{1}{8}, we can now combine these results to find the value of the entire expression: 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3}. This involves multiplying the two simplified values together. Combining results is a crucial step in solving mathematical expressions. We have:

1612ร—2โˆ’3=4ร—1816^{\frac{1}{2}} \times 2^{-3} = 4 \times \frac{1}{8}

To multiply a whole number by a fraction, we can express the whole number as a fraction with a denominator of 1. So, 4 can be written as 41\frac{4}{1}. Now we have:

41ร—18\frac{4}{1} \times \frac{1}{8}

To multiply fractions, we multiply the numerators together and the denominators together:

4ร—11ร—8=48\frac{4 \times 1}{1 \times 8} = \frac{4}{8}

Now we need to simplify the fraction 48\frac{4}{8}. Both the numerator and the denominator are divisible by 4. Dividing both by 4, we get:

4รท48รท4=12\frac{4 \div 4}{8 \div 4} = \frac{1}{2}

Therefore, the simplified fraction is 12\frac{1}{2}. This final step demonstrates the importance of simplifying fractions to their lowest terms. Simplifying fractions is a fundamental skill in mathematics and ensures that the answer is presented in its most concise form. The ability to identify common factors and divide both the numerator and denominator by them is essential for this process. In this case, recognizing that both 4 and 8 are divisible by 4 allowed us to easily reduce the fraction to its simplest form. This completes the evaluation of the expression. We have successfully combined the results of our previous steps and simplified the fraction to arrive at the final answer.

Final Answer: 12\frac{1}{2}

In conclusion, by meticulously evaluating each component of the expression 1612ร—2โˆ’316^{\frac{1}{2}} \times 2^{-3}, we have arrived at the final answer. We first simplified 161216^{\frac{1}{2}} to 4 by recognizing that a fractional exponent of 12\frac{1}{2} represents the square root. Then, we addressed 2โˆ’32^{-3} by applying the rule of negative exponents, which led us to calculate 123\frac{1}{2^3}, resulting in 18\frac{1}{8}. Finally, we multiplied these simplified values together: 4ร—184 \times \frac{1}{8}, which simplified to 48\frac{4}{8}. By reducing this fraction to its simplest form, we obtained the final answer of 12\frac{1}{2}. The final answer of this mathematical exploration is 12\frac{1}{2}. This journey through exponent manipulation and simplification techniques has highlighted the importance of understanding the fundamental rules of exponents, fractional powers, and negative exponents. Each step, from evaluating the square root to handling the negative exponent and simplifying the resulting fraction, required a clear understanding of mathematical principles. This problem serves as an excellent example of how a seemingly complex expression can be broken down into manageable parts and solved systematically. The skills acquired in this process are invaluable for tackling more advanced mathematical challenges. Furthermore, the emphasis on presenting the final answer as a fraction in its simplest form underscores the importance of precision and attention to detail in mathematics. We hope this comprehensive guide has provided you with a clear and concise understanding of how to evaluate such expressions and that you feel more confident in your ability to tackle similar problems in the future. The key takeaways from this exercise include the ability to interpret fractional and negative exponents, apply the rules of exponents, and simplify fractions. These skills are essential building blocks for further mathematical studies and are widely applicable in various fields of science and engineering.