Equation Of A Circle With Center (-4, 9) And Diameter 10

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This article delves into the fascinating world of circles and their equations, providing a comprehensive guide to understanding and solving problems related to circles in coordinate geometry. We will specifically address the question: Which equation represents a circle with a center at (-4, 9) and a diameter of 10 units? This question is a classic example of how to apply the standard equation of a circle, and we will break down each step to ensure clarity and comprehension.

Understanding the Standard Equation of a Circle

The foundation for solving this problem lies in understanding the standard equation of a circle. In coordinate geometry, a circle is defined as the set of all points equidistant from a central point. This fixed distance is known as the radius, and the central point is the center of the circle. The standard equation of a circle provides a concise way to represent this geometric definition algebraically. The standard form equation is expressed as:

(x - h)² + (y - k)² = r²

Where:

  • (h, k) represents the coordinates of the center of the circle.
  • r represents the radius of the circle.
  • (x, y) represents any point on the circumference of the circle.

This equation stems directly from the Pythagorean theorem, which relates the sides of a right-angled triangle. Imagine a right triangle formed by a point (x, y) on the circle, the center of the circle (h, k), and a point directly below or to the side of (x, y) that shares either the x or y coordinate with the center. The legs of this triangle have lengths |x - h| and |y - k|, and the hypotenuse is the radius, r. Applying the Pythagorean theorem (a² + b² = c²) gives us the standard equation of the circle.

The standard equation is a powerful tool because it allows us to immediately identify the center and radius of a circle given its equation, and conversely, to write the equation of a circle given its center and radius. Let's delve deeper into the significance of each component.

The Center (h, k)

The center of the circle, denoted by the coordinates (h, k), is the focal point around which the circle is drawn. It is the point from which all points on the circle are equidistant. In the standard equation, 'h' represents the x-coordinate of the center, and 'k' represents the y-coordinate. It's crucial to note the negative signs in the equation: (x - h) and (y - k). This means that if the equation shows (x + 4), the x-coordinate of the center is actually -4, and similarly, if the equation shows (y - 9), the y-coordinate of the center is 9. Understanding this sign convention is vital for correctly identifying the center from the equation.

The Radius (r)

The radius of the circle, denoted by 'r', is the distance from the center to any point on the circle. It's a constant value that defines the size of the circle. In the standard equation, 'r' appears squared (r²). This is an important point to remember when working with circle equations. If you are given the radius, you need to square it to find the value that appears in the equation. Conversely, if you are given the value in the equation, you need to take the square root to find the radius. For example, if the equation shows r² = 25, then the radius is √25 = 5.

Applying the Standard Equation to the Problem

Now that we have a firm grasp of the standard equation of a circle, let's apply it to the problem at hand. The question asks us to identify the equation that represents a circle with a center at (-4, 9) and a diameter of 10 units. The key here is to carefully translate the given information into the components of the standard equation.

Identifying the Center

The center of the circle is given as (-4, 9). This means that h = -4 and k = 9. We will substitute these values into the standard equation:

(x - h)² + (y - k)² = r²

becomes:

(x - (-4))² + (y - 9)² = r²

Simplifying the double negative, we get:

(x + 4)² + (y - 9)² = r²

Determining the Radius

The diameter of the circle is given as 10 units. However, the standard equation uses the radius, not the diameter. Remember that the radius is half the diameter. Therefore, the radius of this circle is 10 / 2 = 5 units. Now, we need to square the radius to find the value of r²:

r² = 5² = 25

Constructing the Equation

Now we have all the necessary components to write the equation of the circle. We have the center (-4, 9), which gives us (x + 4)² and (y - 9)², and we have the radius squared, r² = 25. Substituting these values into the standard equation, we get:

(x + 4)² + (y - 9)² = 25

This is the equation that represents a circle with a center at (-4, 9) and a diameter of 10 units.

Analyzing the Answer Choices

Now, let's examine the answer choices provided in the original question and see which one matches our derived equation:

A. (x - 9)² + (y + 4)² = 25 B. (x + 4)² + (y - 9)² = 25 C. (x - 9)² + (y + 4)² = 100 D. (x + 4)² + (y - 9)² = 100

By comparing our derived equation with the answer choices, we can clearly see that option B, (x + 4)² + (y - 9)² = 25, is the correct answer. Options A and C have the center coordinates reversed and with incorrect signs, while option D has the correct center but an incorrect radius (100 instead of 25).

Common Mistakes and How to Avoid Them

When working with circle equations, there are several common mistakes that students often make. Being aware of these pitfalls can help you avoid them and ensure accuracy in your solutions.

Confusing Radius and Diameter

One of the most common mistakes is confusing the radius and diameter. Remember that the radius is half the diameter. If a problem gives you the diameter, you must divide it by 2 to find the radius before using it in the standard equation. Similarly, if the equation gives you r², remember to take the square root to find the radius.

Incorrectly Identifying the Center Coordinates

Another frequent error is misidentifying the center coordinates from the equation. Remember the negative signs in the standard equation: (x - h) and (y - k). This means that the coordinates of the center are the opposite of the values that appear in the equation. For example, if the equation has (x + 4), the x-coordinate of the center is -4, not 4.

Forgetting to Square the Radius

It's also a common mistake to forget to square the radius when writing the equation. The standard equation uses r², not r. So, if you calculate the radius as 5, you need to square it to get 25, which is the value that appears in the equation.

Sign Errors

Sign errors are particularly common when substituting the center coordinates into the equation. Be careful with negative signs. For example, if the center is (-4, 9), the equation will have (x - (-4)), which simplifies to (x + 4), and (y - 9).

Algebraic Mistakes

Finally, be mindful of algebraic mistakes when manipulating the equation. Ensure you are correctly expanding squares, combining like terms, and performing any other algebraic operations. A small error in algebra can lead to an incorrect final answer.

Tips for Solving Circle Equation Problems

To master circle equation problems, consider the following tips:

  1. Memorize the Standard Equation: The standard equation of a circle is the foundation for solving these problems. Make sure you know it well.
  2. Identify the Center and Radius: Practice extracting the center and radius from a given equation and vice versa.
  3. Pay Attention to Detail: Circle equation problems often involve subtle details, such as the difference between radius and diameter or the signs of the center coordinates. Read the problem carefully and pay attention to these details.
  4. Draw a Diagram: If you're struggling to visualize the problem, try drawing a diagram. Sketching the circle and its center can help you understand the relationships between the different components.
  5. Check Your Work: Always double-check your work to catch any potential errors. Make sure you have correctly identified the center and radius, and that you have substituted them into the equation correctly.
  6. Practice Regularly: Like any mathematical skill, solving circle equation problems requires practice. Work through a variety of examples to build your confidence and proficiency.

Conclusion

In conclusion, the equation that represents a circle with a center at (-4, 9) and a diameter of 10 units is (x + 4)² + (y - 9)² = 25. This solution is derived by understanding and applying the standard equation of a circle, (x - h)² + (y - k)² = r², where (h, k) is the center and r is the radius. By carefully identifying the center coordinates and the radius, and by avoiding common mistakes such as confusing radius and diameter or making sign errors, you can confidently solve these types of problems. Remember to practice regularly and pay attention to detail to master the concepts of circle equations in coordinate geometry. With a solid understanding of the standard equation and consistent practice, you can successfully tackle any circle-related problem that comes your way.

This comprehensive guide has equipped you with the knowledge and skills to confidently approach circle equation problems. Remember to understand the fundamentals, practice consistently, and pay attention to detail, and you'll be well on your way to mastering this essential concept in coordinate geometry.