Circle Equation Find The Right Equation For Center (-5 5) And Radius 3

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In the realm of mathematics, circles hold a fundamental place, and their equations provide a powerful tool for describing and analyzing these geometric shapes. The equation of a circle not only defines its shape but also pinpoint its position in the coordinate plane. This article delves deep into the standard equation of a circle and guides you through the process of identifying the correct equation given the circle's center and radius. We will dissect the key components of the equation, explore common pitfalls, and solidify your understanding with a step-by-step approach to solving problems related to circle equations. By the end of this exploration, you will be equipped to confidently tackle any question involving the equation of a circle.

The standard form equation serves as the cornerstone for representing circles in the Cartesian coordinate system. It elegantly encapsulates the two essential attributes of a circle: its center and its radius. This equation allows us to precisely describe a circle's position and size on a graph. Understanding the relationship between the equation and the circle's properties is crucial for various mathematical applications, from geometry problems to calculus and beyond. We will break down the equation into its individual components and explain how each contributes to defining the circle. Furthermore, we will emphasize the importance of correctly interpreting the signs and values within the equation to avoid common errors. By mastering the standard form equation, you unlock a powerful tool for analyzing and manipulating circles in a mathematical context. This detailed explanation will serve as a solid foundation for understanding the more complex problem and its solution.

We are presented with a classic problem that tests our understanding of the standard equation of a circle. The core of the problem lies in the ability to translate the given information – the circle's center and radius – into the correct algebraic representation. This process involves recognizing the relationship between the center's coordinates and the terms within the equation, as well as understanding how the radius relates to the equation's constant term. The problem also serves as a reminder of the subtle yet crucial role that signs play in the equation. A seemingly minor error in sign can lead to a completely different circle, highlighting the need for careful attention to detail. Therefore, solving this problem effectively requires not only a conceptual understanding of the equation but also a meticulous approach to applying it. Our method to solve this problem involves a direct application of the standard equation of a circle. By correctly substituting the given values for the center and radius, we can arrive at the answer efficiently. This method emphasizes a clear, step-by-step approach, minimizing the chance of errors and maximizing clarity. By following this approach, you will gain confidence in your ability to solve similar problems in the future.

The standard equation of a circle is given by: (x - h)² + (y - k)² = r² where (h, k) represents the coordinates of the center of the circle, and r denotes the radius. This equation is derived from the Pythagorean theorem, reflecting the relationship between the distances on a coordinate plane and the radius of the circle. The terms (x - h) and (y - k) represent the horizontal and vertical distances from any point (x, y) on the circle to the center (h, k), respectively. Squaring these distances and summing them gives us the square of the radius, r². This fundamental relationship is what dictates the circular shape. Therefore, understanding how each component of the equation contributes to defining the circle's characteristics is paramount for solving related problems.

The center coordinates (h, k) play a pivotal role in positioning the circle on the coordinate plane. The values of h and k directly correspond to the x and y coordinates of the circle's center, respectively. However, it is crucial to note that the signs in the equation are opposite to the signs of the center coordinates. For instance, if the equation contains the term (x - 3)², it indicates that the x-coordinate of the center is +3, not -3. Similarly, (y + 2)² implies a y-coordinate of -2. This sign reversal is a common source of errors, so careful attention to detail is essential. Visualizing the circle on a graph can aid in understanding this relationship. By plotting the center and considering the radius, one can develop a strong intuitive grasp of how the equation translates into a geometric representation. The center, being the fixed point around which the circle is drawn, is fundamental to defining its location.

The radius (r), on the other hand, determines the size of the circle. It represents the constant distance from the center to any point on the circle's circumference. In the standard equation, the radius is squared (r²), so to find the actual radius, we must take the square root of the constant term on the right side of the equation. For example, if the equation is (x - h)² + (y - k)² = 16, then r² = 16, and the radius is r = √16 = 4 units. The radius is a fundamental property of the circle, dictating its extent in all directions from the center. A larger radius implies a larger circle, while a smaller radius signifies a smaller circle. The relationship between the radius and the equation is straightforward, but it is essential to remember the squaring and square root operations when moving between the equation and the circle's geometric properties. Understanding the role of the radius is critical for accurately interpreting and manipulating circle equations.

In this specific problem, we are given that the center of the circle is at (-5, 5), which means h = -5 and k = 5. This information directly feeds into the standard equation, where we substitute these values for h and k. Remembering the sign reversal, we will have (x - (-5)) which simplifies to (x + 5) and (y - 5) remaining as is. The center coordinates are the anchor of our circle, dictating its position on the coordinate plane. Accurately identifying and substituting these values is the first critical step in finding the correct equation. Any error in this step will propagate through the rest of the solution, highlighting the importance of meticulousness.

We are also given that the radius of the circle is 3 units. In the standard equation, the radius is squared, so we need to calculate r², which is 3² = 9. This value will be the constant term on the right side of the equation. The radius, as discussed earlier, dictates the size of the circle, and its square directly appears in the equation. Failing to square the radius is a common mistake, so it is vital to remember this step. Once we have calculated r², we have all the necessary information to construct the complete equation of the circle.

Now, let's combine the information about the center and the radius. We have h = -5, k = 5, and r² = 9. Substituting these values into the standard equation (x - h)² + (y - k)² = r², we get (x - (-5))² + (y - 5)² = 9. Simplifying this, we arrive at (x + 5)² + (y - 5)² = 9. This equation now precisely describes the circle with the given center and radius. It encapsulates all the essential geometric information in a concise algebraic form. The equation allows us to not only visualize the circle but also perform various mathematical operations on it, such as finding points on the circle or determining its intersection with other geometric shapes. This step-by-step substitution process ensures that we accurately translate the given information into the correct equation, minimizing the risk of errors.

Now that we have derived the equation (x + 5)² + (y - 5)² = 9, we can compare it to the given options. Option A, (x+5)²+(y-5)²=3, is incorrect because the right side of the equation should be r², which is 9, not 3. Option B, (x+5)²+(y-5)²=6, is also incorrect for the same reason; the right side should be 9. Option D, (x-5)²+(y+5)²=3, is incorrect because it has the wrong signs for the center coordinates and the wrong value for r². Option E, (x-5)²+(y+5)²=9, is incorrect because it has the wrong signs for the center coordinates. The presence of incorrect signs or radius values highlights the importance of understanding the components of the standard equation. These options serve as distractors, designed to test your understanding of the relationship between the center, radius, and the equation.

Option C, (x+5)²+(y-5)²=9, perfectly matches the equation we derived. It has the correct signs for the center coordinates (-5, 5) and the correct value for r², which is 9. Therefore, option C is the correct answer. The process of elimination can be a powerful tool in multiple-choice questions. By systematically ruling out incorrect options, we can increase our confidence in the correct answer. In this case, comparing each option to our derived equation allows us to identify the perfect match.

The correct answer is C. (x+5)²+(y-5)²=9. This equation accurately represents a circle with a center at (-5, 5) and a radius of 3 units. This solution demonstrates the importance of understanding the standard equation of a circle and applying it correctly. By breaking down the problem into smaller steps and paying attention to detail, we can confidently arrive at the right answer. This problem not only tests your knowledge of the equation but also your ability to translate geometric information into algebraic form. Mastering this skill is essential for success in mathematics and related fields.

In summary, the key to solving this problem lies in understanding the standard equation of a circle, (x - h)² + (y - k)² = r², and correctly substituting the given values for the center (h, k) and radius r. Remember to square the radius when placing it in the equation and to pay close attention to the signs of the center coordinates. A meticulous step-by-step approach minimizes the chance of errors. This fundamental concept forms the basis for many advanced topics in geometry and calculus. Therefore, a solid understanding of circle equations is crucial for further mathematical exploration.

To solidify your understanding, consider practicing more problems involving circle equations. Try varying the given information, such as providing the diameter instead of the radius or giving the equation and asking for the center and radius. Challenging yourself with different types of problems will strengthen your grasp of the concepts. Additionally, exploring applications of circle equations in real-world scenarios can enhance your appreciation for their practical significance. For example, consider problems involving the design of circular structures or the motion of objects in circular paths. The more you practice, the more confident and proficient you will become in working with circle equations. Consistent practice is the cornerstone of mathematical mastery.

Furthermore, delving into related concepts such as the equation of a line, conic sections, and coordinate geometry can provide a broader context for understanding circle equations. Exploring the relationships between different geometric shapes and their algebraic representations will deepen your mathematical understanding. For example, studying conic sections, which include circles, ellipses, parabolas, and hyperbolas, will reveal the common underlying principles that govern these shapes. Similarly, understanding the connection between geometry and algebra, known as coordinate geometry, will empower you to solve a wider range of problems. Continuous learning and exploration are essential for expanding your mathematical horizons. By venturing beyond the basics, you will discover the interconnectedness of mathematical ideas and develop a more holistic understanding of the subject.

Find the equation of a circle with center (2, -3) and radius 4.

Answer

(x - 2)² + (y + 3)² = 16